perl
  • perl
Oil consumption is increasing at a rate of 1.9% per year. What is its doubling time? I'm not sure if this is linear increase or exponential. if its linear
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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perl
  • perl
, no , this website says its exponential http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.112025.html
perl
  • perl
, if its linear then y = Ao ( 1 + .06*t ) if its exponential then y = Ao ( 1 + .06)^t
anonymous
  • anonymous
i think its exponential 2 = 1 ( 1 + 0.06)^t now calculate t

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anonymous
  • anonymous
Oh, wait. That's right. I apologize. I graphed it wrong.
perl
  • perl
how will i know if its exponential or not?
perl
  • perl
here is another example http://www.physics.uoguelph.ca/tutorials/exp/intro.html
perl
  • perl
why isnt the following example linear ? "For example, let's look at a population of wee beasties which increases by 10% per year. If there were 100 wee beasties now, there would be an increase of 10 wee beasties after a year. "
anonymous
  • anonymous
see in question it increases 1.9% per year first year let consumption = x next year = 1.9*x/100 later year = 1.9(1.9*x/100)/100 if you plot its graph you get exponential curve try it
anonymous
  • anonymous
in your second example population first year = 100 population second year = 110 population third year = 121 it also not linear
perl
  • perl
you need a plus somewhere
perl
  • perl
it should be next year consumption = last year consumption* ( 1 + 1.9/100)
anonymous
  • anonymous
yes you are write
perl
  • perl
so we have x1 = x x2 = x1 (1.019) x3 = x2 (1.019) = [x1 (1.019) (1.019) ]
perl
  • perl
better start with zero, x0 = x x1 = x0 (1.019) x2 = x1 (1.019) = [x0 (1.019) ] (1.019) = x0 (1.019) ^2
anonymous
  • anonymous
calculate x1,x2 ,x3 and try to find x2 - x1 = x3 -x2 if its write then only its linear
perl
  • perl
so did you agree with my math?
perl
  • perl
right, clearly x2-x1 != x3 - x2
anonymous
  • anonymous
yes i agree so what you think its linear or exponential
perl
  • perl
well... exponential
perl
  • perl
i think its a little ambiguous however
perl
  • perl
, you could also have y = x0 ( 1 + .019 * t ) , no ?
perl
  • perl
ok how would you word it so that it is linear?
anonymous
  • anonymous
let if increase every year is same then its linear for example if population of city inc by 20 people every year then we can say that its linear
perl
  • perl
ok , so we wouldnt use percentage for a linear increase
anonymous
  • anonymous
yes
perl
  • perl
if there is a percentage growth , like population percentage growth , grows at a constant percentage, it is exponential growth
anonymous
  • anonymous
yes
perl
  • perl
got it,
anonymous
  • anonymous
ok then
perl
  • perl
ok now doubling time makes sense
perl
  • perl
doubling time is the time it takes for the initial amount to grow 100% , leaving you with double
anonymous
  • anonymous
yes did you get your answer?
perl
  • perl
yes, the math i didnt have trouble with. just the understanding
perl
  • perl
i have a much harder problem, differential equation
perl
  • perl
are you ready?
perl
  • perl
its a logistic growth problem
anonymous
  • anonymous
ok then now you can close the qustion after giving me medal...............lol
perl
  • perl
you stuck it out , good work
perl
  • perl
the rest bailed

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