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perl Group Title

Oil consumption is increasing at a rate of 1.9% per year. What is its doubling time? I'm not sure if this is linear increase or exponential. if its linear

  • one year ago
  • one year ago

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  1. perl Group Title
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    , no , this website says its exponential http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.112025.html

    • one year ago
  2. perl Group Title
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    , if its linear then y = Ao ( 1 + .06*t ) if its exponential then y = Ao ( 1 + .06)^t

    • one year ago
  3. uzumakhi Group Title
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    i think its exponential 2 = 1 ( 1 + 0.06)^t now calculate t

    • one year ago
  4. radh Group Title
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    Oh, wait. That's right. I apologize. I graphed it wrong.

    • one year ago
  5. perl Group Title
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    how will i know if its exponential or not?

    • one year ago
  6. perl Group Title
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    here is another example http://www.physics.uoguelph.ca/tutorials/exp/intro.html

    • one year ago
  7. perl Group Title
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    why isnt the following example linear ? "For example, let's look at a population of wee beasties which increases by 10% per year. If there were 100 wee beasties now, there would be an increase of 10 wee beasties after a year. "

    • one year ago
  8. uzumakhi Group Title
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    see in question it increases 1.9% per year first year let consumption = x next year = 1.9*x/100 later year = 1.9(1.9*x/100)/100 if you plot its graph you get exponential curve try it

    • one year ago
  9. uzumakhi Group Title
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    in your second example population first year = 100 population second year = 110 population third year = 121 it also not linear

    • one year ago
  10. perl Group Title
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    you need a plus somewhere

    • one year ago
  11. perl Group Title
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    it should be next year consumption = last year consumption* ( 1 + 1.9/100)

    • one year ago
  12. uzumakhi Group Title
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    yes you are write

    • one year ago
  13. perl Group Title
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    so we have x1 = x x2 = x1 (1.019) x3 = x2 (1.019) = [x1 (1.019) (1.019) ]

    • one year ago
  14. perl Group Title
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    better start with zero, x0 = x x1 = x0 (1.019) x2 = x1 (1.019) = [x0 (1.019) ] (1.019) = x0 (1.019) ^2

    • one year ago
  15. uzumakhi Group Title
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    calculate x1,x2 ,x3 and try to find x2 - x1 = x3 -x2 if its write then only its linear

    • one year ago
  16. perl Group Title
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    so did you agree with my math?

    • one year ago
  17. perl Group Title
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    right, clearly x2-x1 != x3 - x2

    • one year ago
  18. uzumakhi Group Title
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    yes i agree so what you think its linear or exponential

    • one year ago
  19. perl Group Title
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    well... exponential

    • one year ago
  20. perl Group Title
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    i think its a little ambiguous however

    • one year ago
  21. perl Group Title
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    , you could also have y = x0 ( 1 + .019 * t ) , no ?

    • one year ago
  22. perl Group Title
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    ok how would you word it so that it is linear?

    • one year ago
  23. uzumakhi Group Title
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    let if increase every year is same then its linear for example if population of city inc by 20 people every year then we can say that its linear

    • one year ago
  24. perl Group Title
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    ok , so we wouldnt use percentage for a linear increase

    • one year ago
  25. uzumakhi Group Title
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    yes

    • one year ago
  26. perl Group Title
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    if there is a percentage growth , like population percentage growth , grows at a constant percentage, it is exponential growth

    • one year ago
  27. uzumakhi Group Title
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    yes

    • one year ago
  28. perl Group Title
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    got it,

    • one year ago
  29. uzumakhi Group Title
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    ok then

    • one year ago
  30. perl Group Title
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    ok now doubling time makes sense

    • one year ago
  31. perl Group Title
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    doubling time is the time it takes for the initial amount to grow 100% , leaving you with double

    • one year ago
  32. uzumakhi Group Title
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    yes did you get your answer?

    • one year ago
  33. perl Group Title
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    yes, the math i didnt have trouble with. just the understanding

    • one year ago
  34. perl Group Title
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    i have a much harder problem, differential equation

    • one year ago
  35. perl Group Title
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    are you ready?

    • one year ago
  36. perl Group Title
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    its a logistic growth problem

    • one year ago
  37. uzumakhi Group Title
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    ok then now you can close the qustion after giving me medal...............lol

    • one year ago
  38. perl Group Title
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    you stuck it out , good work

    • one year ago
  39. perl Group Title
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    the rest bailed

    • one year ago
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