Oil consumption is increasing at a rate of 1.9% per year. What is its doubling time?
I'm not sure if this is linear increase or exponential.
if its linear

- perl

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- perl

, no , this website says its exponential
http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.112025.html

- perl

, if its linear then
y = Ao ( 1 + .06*t )
if its exponential then
y = Ao ( 1 + .06)^t

- anonymous

i think its exponential
2 = 1 ( 1 + 0.06)^t
now calculate t

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Oh, wait. That's right. I apologize. I graphed it wrong.

- perl

how will i know if its exponential or not?

- perl

here is another example
http://www.physics.uoguelph.ca/tutorials/exp/intro.html

- perl

why isnt the following example linear ?
"For example, let's look at a population of wee beasties which increases by 10% per year. If there were 100 wee beasties now, there would be an increase of 10 wee beasties after a year. "

- anonymous

see in question it increases 1.9% per year
first year let consumption = x
next year = 1.9*x/100
later year = 1.9(1.9*x/100)/100
if you plot its graph you get exponential curve
try it

- anonymous

in your second example
population first year = 100
population second year = 110
population third year = 121
it also not linear

- perl

you need a plus somewhere

- perl

it should be
next year consumption = last year consumption* ( 1 + 1.9/100)

- anonymous

yes you are write

- perl

so we have
x1 = x
x2 = x1 (1.019)
x3 = x2 (1.019) = [x1 (1.019) (1.019) ]

- perl

better start with zero,
x0 = x
x1 = x0 (1.019)
x2 = x1 (1.019) = [x0 (1.019) ] (1.019) = x0 (1.019) ^2

- anonymous

calculate x1,x2 ,x3
and try to find
x2 - x1 = x3 -x2
if its write then only its linear

- perl

so did you agree with my math?

- perl

right, clearly x2-x1 != x3 - x2

- anonymous

yes i agree
so what you think
its linear or exponential

- perl

well... exponential

- perl

i think its a little ambiguous however

- perl

, you could also have
y = x0 ( 1 + .019 * t ) , no ?

- perl

ok how would you word it so that it is linear?

- anonymous

let if increase every year is same then its linear
for example
if population of city inc by 20 people every year
then we can say that its linear

- perl

ok , so we wouldnt use percentage for a linear increase

- anonymous

yes

- perl

if there is a percentage growth , like population percentage growth , grows at a constant percentage, it is exponential growth

- anonymous

yes

- perl

got it,

- anonymous

ok then

- perl

ok now doubling time makes sense

- perl

doubling time is the time it takes for the initial amount to grow 100%
, leaving you with double

- anonymous

yes
did you get your answer?

- perl

yes, the math i didnt have trouble with. just the understanding

- perl

i have a much harder problem, differential equation

- perl

are you ready?

- perl

its a logistic growth problem

- anonymous

ok then
now you can close the qustion
after giving me medal...............lol

- perl

you stuck it out , good work

- perl

the rest bailed

Looking for something else?

Not the answer you are looking for? Search for more explanations.