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perl

  • 2 years ago

Oil consumption is increasing at a rate of 1.9% per year. What is its doubling time? I'm not sure if this is linear increase or exponential. if its linear

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  1. perl
    • 2 years ago
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    , no , this website says its exponential http://www.algebra.com/algebra/homework/logarithm/logarithm.faq.question.112025.html

  2. perl
    • 2 years ago
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    , if its linear then y = Ao ( 1 + .06*t ) if its exponential then y = Ao ( 1 + .06)^t

  3. uzumakhi
    • 2 years ago
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    i think its exponential 2 = 1 ( 1 + 0.06)^t now calculate t

  4. radh
    • 2 years ago
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    Oh, wait. That's right. I apologize. I graphed it wrong.

  5. perl
    • 2 years ago
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    how will i know if its exponential or not?

  6. perl
    • 2 years ago
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    here is another example http://www.physics.uoguelph.ca/tutorials/exp/intro.html

  7. perl
    • 2 years ago
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    why isnt the following example linear ? "For example, let's look at a population of wee beasties which increases by 10% per year. If there were 100 wee beasties now, there would be an increase of 10 wee beasties after a year. "

  8. uzumakhi
    • 2 years ago
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    see in question it increases 1.9% per year first year let consumption = x next year = 1.9*x/100 later year = 1.9(1.9*x/100)/100 if you plot its graph you get exponential curve try it

  9. uzumakhi
    • 2 years ago
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    in your second example population first year = 100 population second year = 110 population third year = 121 it also not linear

  10. perl
    • 2 years ago
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    you need a plus somewhere

  11. perl
    • 2 years ago
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    it should be next year consumption = last year consumption* ( 1 + 1.9/100)

  12. uzumakhi
    • 2 years ago
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    yes you are write

  13. perl
    • 2 years ago
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    so we have x1 = x x2 = x1 (1.019) x3 = x2 (1.019) = [x1 (1.019) (1.019) ]

  14. perl
    • 2 years ago
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    better start with zero, x0 = x x1 = x0 (1.019) x2 = x1 (1.019) = [x0 (1.019) ] (1.019) = x0 (1.019) ^2

  15. uzumakhi
    • 2 years ago
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    calculate x1,x2 ,x3 and try to find x2 - x1 = x3 -x2 if its write then only its linear

  16. perl
    • 2 years ago
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    so did you agree with my math?

  17. perl
    • 2 years ago
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    right, clearly x2-x1 != x3 - x2

  18. uzumakhi
    • 2 years ago
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    yes i agree so what you think its linear or exponential

  19. perl
    • 2 years ago
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    well... exponential

  20. perl
    • 2 years ago
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    i think its a little ambiguous however

  21. perl
    • 2 years ago
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    , you could also have y = x0 ( 1 + .019 * t ) , no ?

  22. perl
    • 2 years ago
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    ok how would you word it so that it is linear?

  23. uzumakhi
    • 2 years ago
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    let if increase every year is same then its linear for example if population of city inc by 20 people every year then we can say that its linear

  24. perl
    • 2 years ago
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    ok , so we wouldnt use percentage for a linear increase

  25. uzumakhi
    • 2 years ago
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    yes

  26. perl
    • 2 years ago
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    if there is a percentage growth , like population percentage growth , grows at a constant percentage, it is exponential growth

  27. uzumakhi
    • 2 years ago
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    yes

  28. perl
    • 2 years ago
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    got it,

  29. uzumakhi
    • 2 years ago
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    ok then

  30. perl
    • 2 years ago
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    ok now doubling time makes sense

  31. perl
    • 2 years ago
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    doubling time is the time it takes for the initial amount to grow 100% , leaving you with double

  32. uzumakhi
    • 2 years ago
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    yes did you get your answer?

  33. perl
    • 2 years ago
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    yes, the math i didnt have trouble with. just the understanding

  34. perl
    • 2 years ago
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    i have a much harder problem, differential equation

  35. perl
    • 2 years ago
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    are you ready?

  36. perl
    • 2 years ago
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    its a logistic growth problem

  37. uzumakhi
    • 2 years ago
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    ok then now you can close the qustion after giving me medal...............lol

  38. perl
    • 2 years ago
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    you stuck it out , good work

  39. perl
    • 2 years ago
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    the rest bailed

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