Solve graphing.

- anonymous

Solve graphing.

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- anonymous

\[y = - \frac{ 3 }{ 2}x + 4\]
How would I solve that? How would I do the Rise over Run when my fraction is negative?

- anonymous

@DarienCollup @Solmyr @Faman39 @KatherinePierce1864 @AlexPR787 @dennisjr

- anonymous

@lovekblue

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## More answers

- Hero

Graph the first three points, then draw a line through them

- anonymous

HOw would I graph the fraction part?

- Hero

You're focusing too much on the "fraction part". What you will be graphing are points on a line.

- Hero

Remember, you still have y = mx + b, which is the formula for a line. The fraction part only represents the slope of the line.

- anonymous

Huh? What do you mean?

- anonymous

My school is telling me that I would graph (0, 4) and then graph the fraction with rise over run, but the fraction is negative and I don't know how to work with it.

- Hero

Just focus on graphing the points.

- Hero

Focus on the x and y intercepts

- anonymous

I don't understand.

- anonymous

Wouldn't I graph 4?

- Hero

You found one of the points: (0,4)

- Hero

Now find the x-intercept. Set y = 0, then solve for x

- anonymous

Uhhh..

- Hero

Do you have any clue what's going on here?

- anonymous

I'm left with a fraction still. I don't know how to graph that fraction.
I know it would be an rise over run process, but the fraction is negative. That changes it for me.

- anonymous

What you need to graph is a straight line and the most important parts relating to it such as the x and y intercepts if they are any, in this case there are both.

- anonymous

What happens when the fraction is negative? Does it change? Would I make the 3 negative? Would both the numbers be negative?

- anonymous

I'm not graphing both the intercepts. It says graph the y-intercept first, and graph the slope, which is the fraction?

- anonymous

just the 3 is negative.

- anonymous

When you graph the two intercepts and connect them, it will automatically contain the slope/gradient of the line.

- anonymous

so (-3, 2)

- Hero

\[y = - \frac{ 3 }{ 2}x + 4\]
\[0 = - \frac{ 3 }{ 2}x + 4\]
\[\frac{ 3 }{ 2}x = 4\]
\[\frac{ 3x }{ 2} = 4\]
\[3x = 8\]
\[x = \frac{8}{3}\]
\[x = 2\frac{2}{3}\]

- anonymous

Slope/gradient is found by \[M = \frac{y2-y1}{x2-x1}\] or rise/run
your rise is -3 and run is 2

- Hero

So the other point is \[(2.67, 0)\]

- anonymous

I think it just wants one answer .-.

- anonymous

This is basic 9th grade math.

- Hero

No, you need at least two points to graph a line. You can't graph a line with only one point.

- Hero

Didn't your teacher go over this with you?

- anonymous

I mean, I think they want me to find the rise over run by graphing (-3, 2) and 4.

- Hero

You already have the rise over run

- Hero

-3/4 is the rise over run

- anonymous

So:
\[-\frac{ 3 }{ 2 } = \frac{ -3 }{ 2 }\] Is this correct? When dealing with a negative fraction in rise over run, the top number becomes negative when putting it into an ordered pair?

- anonymous

?

- Hero

Ask your teacher about it. You are too confused.

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