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Solve graphing.

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\[y = - \frac{ 3 }{ 2}x + 4\] How would I solve that? How would I do the Rise over Run when my fraction is negative?

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Other answers:

Graph the first three points, then draw a line through them
HOw would I graph the fraction part?
You're focusing too much on the "fraction part". What you will be graphing are points on a line.
Remember, you still have y = mx + b, which is the formula for a line. The fraction part only represents the slope of the line.
Huh? What do you mean?
My school is telling me that I would graph (0, 4) and then graph the fraction with rise over run, but the fraction is negative and I don't know how to work with it.
Just focus on graphing the points.
Focus on the x and y intercepts
I don't understand.
Wouldn't I graph 4?
You found one of the points: (0,4)
Now find the x-intercept. Set y = 0, then solve for x
Do you have any clue what's going on here?
I'm left with a fraction still. I don't know how to graph that fraction. I know it would be an rise over run process, but the fraction is negative. That changes it for me.
What you need to graph is a straight line and the most important parts relating to it such as the x and y intercepts if they are any, in this case there are both.
What happens when the fraction is negative? Does it change? Would I make the 3 negative? Would both the numbers be negative?
I'm not graphing both the intercepts. It says graph the y-intercept first, and graph the slope, which is the fraction?
just the 3 is negative.
When you graph the two intercepts and connect them, it will automatically contain the slope/gradient of the line.
so (-3, 2)
\[y = - \frac{ 3 }{ 2}x + 4\] \[0 = - \frac{ 3 }{ 2}x + 4\] \[\frac{ 3 }{ 2}x = 4\] \[\frac{ 3x }{ 2} = 4\] \[3x = 8\] \[x = \frac{8}{3}\] \[x = 2\frac{2}{3}\]
Slope/gradient is found by \[M = \frac{y2-y1}{x2-x1}\] or rise/run your rise is -3 and run is 2
So the other point is \[(2.67, 0)\]
I think it just wants one answer .-.
This is basic 9th grade math.
No, you need at least two points to graph a line. You can't graph a line with only one point.
Didn't your teacher go over this with you?
I mean, I think they want me to find the rise over run by graphing (-3, 2) and 4.
You already have the rise over run
-3/4 is the rise over run
So: \[-\frac{ 3 }{ 2 } = \frac{ -3 }{ 2 }\] Is this correct? When dealing with a negative fraction in rise over run, the top number becomes negative when putting it into an ordered pair?
Ask your teacher about it. You are too confused.

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