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mikala1 Group TitleBest ResponseYou've already chosen the best response.1
@calculusfunctions could you help me i got premission to ask some one on here
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
Do you know how to do this @sue101
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
ok all i need help on is numbers 1 2 and 3 i dont even know how to make the graph and my teacher says it is ok to ask for help on making it aslong as i am doing some of it can some plz help me
 2 years ago

jazy Group TitleBest ResponseYou've already chosen the best response.1
1) x – 3 > –9 Add 3 to both sides. 2) –2x + 1 ≤ –11 Subtract 1 from both sides. Divide by 2 and flip the sign to ≥. 3) 10 < –3x + 1 Subtract 1 from both sides. Divide by 3 and flip the sign to > **Whenever you divide by a negative, you flip the sign. To graph: Less/Greater Than (> or <)... Open Circle Less/Greater Than AND equal to (>= or <=)... Closed Circle Greater than... Shading to the Right Less than... Shading to the left.
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
thank you so much yuo helped alot no lie thank you
 2 years ago

jazy Group TitleBest ResponseYou've already chosen the best response.1
No problem. I'm glad I could help! (:
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
I only ned help on number 4 but they dident know it
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
4. 2(x + 5) > 8x – 8
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
Solve just as you would an equation. Go ahead.
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
Pretend there's an equal sign. 2(x + 5) = 8x  8 Solve for x. What would you get for x @mikala1 ?
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
No. Try again. Show me your steps so that I can see where you're going wrong.
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
Let me get you started with the first step.
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
i added 5 + x with pemdas
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
2(x + 5) = 8x  8 2x + 10 = 8x  8 Understand so far?
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
Ihave come out with this 1. First you multiply the number outside the parentheses by both variables inside the parentheses. 2 multiplied by x=2x and 2 multiplied by 5=10 Now you have 2x + 10 > 8x  8 2. Next you have to combine like terms and get them on separate sides. (It's easier to work with positive numbers.) You want the X's on one side and the plain numbers on the other. 2x + 10 > 8x  8 (8 is negative so you want to add it to the 10 on the other side. But remember: what you do to one side you do to the other.) 2x + 10 > 8x 8 + 8 + 8 (When you add 8 to the negative 8, it makes it 0 so you just get rid of it.) Now you have: 2x + 18 > 8x So now you subtract 2x from both sides: 2x + 18 > 8x 2x 2x You now have: 18 > 6x which means you have combined all the like terms. 3. Now you divide the 6x by 6 to get x by itself: 18 > 6x divided by 6= x You now have: 18 > x (Remember: what you do to on side you do to the other so you have to divide 18 by 6.) 18 divided by 6= 3 4. So when it's all finished it looks like this: 3 > x which basically means 3 is more than x.
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
Yes so why did you ask if you already solved it?
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
no i just relised that i was asking if you could help cheak it to see if it was correct
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
Yup! it is correct!
 2 years ago

mikala1 Group TitleBest ResponseYou've already chosen the best response.1
thank you and do you have any idea how to mak a line thinkg for this on a computer because im virtual schooled and idk how
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.1
dw:1351853689483:dw Open circle because there is no equal sign. Arrow to the left because everything less than 3. Understand?
 2 years ago
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