A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Is this true: 'The only way you can get from one perfect square, q^2, to another, p^2, by multiplying by a constant [i.e. p^2=a^2 q^2] is if q IS that factor [i.e. q^2=a^2]'?
 2 years ago
Is this true: 'The only way you can get from one perfect square, q^2, to another, p^2, by multiplying by a constant [i.e. p^2=a^2 q^2] is if q IS that factor [i.e. q^2=a^2]'?

This Question is Closed

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1'the first square IS that factor' what is 'that' here? factor of whose ? \(b^2=ma^2\)

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1\[q^2=49p^2\]Must \[q=49\]?

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1I've edited it. Is that still ambiguous?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1then i don't think its always true.... q equal 49, is not necessary

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1Of course apart from the trivial case where p=1

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1Counterexample: 6^2= 4 * 2^2 Damn, it's wrong!

henpen
 2 years ago
Best ResponseYou've already chosen the best response.1This popped up in http://www.komal.hu/verseny/feladat.cgi?a=honap&h=201210&t=mat&l=en if anyone's interested...
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.