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anonymous
 3 years ago
PLEASEE HELPP!!!!! SO CONFUSED:/ :(
anonymous
 3 years ago
PLEASEE HELPP!!!!! SO CONFUSED:/ :(

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phi
 3 years ago
Best ResponseYou've already chosen the best response.1a polynomial with real coefficients (that kind people normally work with) may have complex roots. But if they do have complex roots they come in "complex conjugate pairs" that means if one root is a+bi there is another root abi (the imaginary part is negated) in your case you have a 3rd root 6i (the complex conjugate of the 6+i)

phi
 3 years ago
Best ResponseYou've already chosen the best response.1if you have a root x= 4 for example that means x  (4) =0 if you had another root x= 3 that means x3 = 0 (x 4)(x3)=0 would be the polynomial (x+4)(x3)=0 you have to use this idea to find your polynomial

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes now multiply the (x6i)(x6+i) I would write this as ( (x6) i) ((x6) + i) (I just put parens around the real part) now use (a+b)(ab)= a^2  b^2 here a= (x6) and b= i then multiply that mess by (x+4)
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