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DLSBest ResponseYou've already chosen the best response.0
\[C(40,31) + summation(from j=0 \to j=10) C(40+j,10+j)\]
 one year ago

DLSBest ResponseYou've already chosen the best response.0
someone please put it nicely in an equation form!
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351703115405:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351703210822:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351703313107:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Am I correct @experimentX ???
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1351703384969:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Oh yes! that would decrease one step.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
keep using this, probably you would end up with \[ \binom{51}{31}\]
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
something like that ... not so sure.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351703789879:dw
 one year ago

DLSBest ResponseYou've already chosen the best response.0
howdid u solve C(40,31) & C(40,10) thats the main thing !
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
C(40,10) = C(40,30)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351703959025:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1351704198408:dw
 one year ago
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