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\[C(40,31) + summation(from j=0 \to j=10) C(40+j,10+j)\]

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someone please put it nicely in an equation form!

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dw:1351702148391:dw

sauravshakya
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dw:1351703115405:dw

sauravshakya
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dw:1351703210822:dw

sauravshakya
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dw:1351703313107:dw

sauravshakya
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Am I correct @experimentX ???

experimentX
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dw:1351703384969:dw

sauravshakya
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Oh yes! that would decrease one step.

experimentX
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keep using this, probably you would end up with
\[ \binom{51}{31}\]

experimentX
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something like that ... not so sure.

sauravshakya
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dw:1351703789879:dw

DLS
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howdid u solve C(40,31) & C(40,10)
thats the main thing !

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just explain this part

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and its 51 C 20! not 21..

experimentX
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C(40,10) = C(40,30)

sauravshakya
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dw:1351703959025:dw

DLS
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??

sauravshakya
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dw:1351704198408:dw