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DLS
 3 years ago
Simplify..
DLS
 3 years ago
Simplify..

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DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[C(40,31) + summation(from j=0 \to j=10) C(40+j,10+j)\]

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0someone please put it nicely in an equation form!

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351703115405:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351703210822:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351703313107:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2Am I correct @experimentX ???

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1351703384969:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2Oh yes! that would decrease one step.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1keep using this, probably you would end up with \[ \binom{51}{31}\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1something like that ... not so sure.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351703789879:dw

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0howdid u solve C(40,31) & C(40,10) thats the main thing !

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1C(40,10) = C(40,30)

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351703959025:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1351704198408:dw
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