k.rene.s
What is the absolute value of the number?
3 + i



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myininaya
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\[x+yi=\sqrt{x^2+y^2}\]

k.rene.s
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So it's 4?

myininaya
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You have 3+1i.
So Replace x with 3 and y with 1, then evaluate \[\sqrt{3^2+1^2}\]

k.rene.s
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when I solve I get 3.16. but my choices are:
square root 10
4
8
square root 3

k.rene.s
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so it would be square root of 10? Thanks :)

myininaya
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Yes nine plus one is ten.