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experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0are you trying to prove f=ma?

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0i am thinking and striving to prove weight = mass*gravity? how, i was pondering over it

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0this comes from definition ... weight = gravitational force. weight = GmM/R^2 = m GM/R^2 = mg

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0this is my question how weight = gravitational force* mass (not weight @experimentX :) )

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0and i heard that there is a long proof of it i am looking for that

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0weight = gravitation force = m g  well i guess there is since there is lot's of confusion around mass since the definition of mass keeps going round and round around force and inertia. I haven't understood it correctly.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0probably to clear out this circular logic of mass. but weight = mg ... this comes from newton's second law.

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0weight= mass* acceleration due to gravity  probably you made mistake here ... gravity would mean different thing.

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0@experiment i need mathematical explanation of this definition how weight = mass*gravity?

Carl_Pham
 2 years ago
Best ResponseYou've already chosen the best response.0There is no mathematical derivation. That the force exerted by gravity on an object is proportional to its mass is a hypothesis of Newtonian gravitation, confirmed by experiment. It's an observation, not a deduction.

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0@carl_pham everything in this universe has a mathematical explanation and i strongly believe it has some mathematical explanation and it is in the book principia mathematica by newton , albeit i tried hard to understand that but unfortunately i couldn't and once again i must say there is a derivation of this but unfortunately i am unable to find it.

ivanmlerner
 2 years ago
Best ResponseYou've already chosen the best response.0I was writing it for 10 minutes and the page reloaded

ivanmlerner
 2 years ago
Best ResponseYou've already chosen the best response.0The thing is, \[F=ma=mGMr^{2}\]if we notice that we are considering the weight only for objects very close to the surface of the earth, we see that GMr^2=g and even though this radius usually change, we can consider it as constant and equal to the radius of the earth, therefore getting the acceleration g. A more formal explanation involves the same concept, we take a taylor expansion around the radius of the earth of the function GMr^2=g(r) and consider only the first term since we r and the radius of the earth are very close. This provides a more clear view of whats going but is really unnecessary. It is not useful to continue the taylor expansion to include greater heights because the function F is really simple.

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0@ivanmlerner your explanation seems precised . thanks

Carl_Pham
 2 years ago
Best ResponseYou've already chosen the best response.0@ghazi, and interesting faith, but unfortunately you are wrong. Anything derived purely from empirical observation has no mathematical derivation at all. It just is. Obvious examples include the value of the fine structure constant, as well as many other important constants, why the nuclear forces have a finite range, and the Second Law of thermodynamics (the one that says the entropy of the universe is always increasing). Not one of these things has a mathematical, or indeed any explanation. They are simply observable facts that characterize this universe.

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.0agreed, but i'll get you that soon
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