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anonymous
 3 years ago
How many images will be formed if two mirrors are fitted on adjustment walls and one mirror on ceiling?
a2
b5
c7
d11
anonymous
 3 years ago
How many images will be formed if two mirrors are fitted on adjustment walls and one mirror on ceiling? a2 b5 c7 d11

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0please help when u back @ghazi @experimentX

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0Doesnt it depend on what angle you are looking from?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that is only written and i think they mean it will looks like a room dw:1351708086154:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i draw what i understand from the problem

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0@AvengerVirus The figure you have dradw:1351708439753:dwwn. If an object is kept between the two mirrors. Infinite no. of images will be formed.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but the problem say nothing about object so that i don't understand what it mean

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0I mean from what i am seeing i only see like 6 views.. O_O if thats even possible.. And you just confused me .. _

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0I think the two mirrors are on the same wall, otherwise we'd have infinite no. of images. Figure should be like thisdw:1351708694076:dw M1,2 ,3 are the mirrors.

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0M1 and M3 have an angle of 90, how many images form if mirrors have an angle of 90?

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0Then wouldnt it have the reflection of what is on the other mirror?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0may the angel between M1 & M2 is 90 and M3 is up can u draw that i will try

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351708972826:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then the angle between each of them will be 90 could that be right ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0M1 and M2 are on the same wall. There won't be any secondary images between them. Just primary images.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my pic has 3 walls so that could be the meaning of the problem ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so in M1 and M2 we can see 3 images right ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah that could be right.

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0M1 and M2 will have two primary and one secondary. same goes for M2 and M3, M1 and M3 We'll have totally 3 primary and 3 secondary images. 6 images totally

omnomnom
 3 years ago
Best ResponseYou've already chosen the best response.0That's not even in the options

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0oops, then the two mirrors will be on the same wall.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there is formula say 360/n1 where n is the angle but it calculate the image that comes out of two mirrors is there any one for three mirrors ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not on same wall adjacent walls that is at 90 degree

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes that is right but do u have any idea how to know all the images @03225186213

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if u stand in front of one mirror and see your images then there will be 5 images

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0on the mirrors that adjusted on the wall i can see 3 so u mean 2 on the ceiling's mirror ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0one u will see in front mirror 2nd u will see in side mirror and when u looks up it wiil give your 3rd image as well as two other mirrors image in which u will see your image 4th 5th

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats my idea solve it practically by going to hair saloon

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0even than i won't be able to find a ceiling mirror :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@AvengerVirus you have got three mirrors this time right? and did you get your answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is it three mirror system this way? dw:1351715664451:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351715783712:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it should be 12 but due to imposition of one image it will be 121=11

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0could u explain how ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did u used that formula ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use the same formula for the pair of mirrors and then there will be total of 12 with one image imposed by all three, like the mirror on ceiling with one mirror at 90 degrees will give four images, similarly with other it will give 4 and the two mirror adjacent to each other will give 4 total of 12 but one less

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but the formula say 360/901 and that equal 3 why u say 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oops a big mistake, it will be 7 i was writing this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is total of 9 images and two of them are imposed on each other so i am sure it's 7 , up to my knowledge

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is there a possibility that the other 2 image won't be imposed on each other ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes there is if they are not placed at right angle to each other

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so if the angle wasn't 90 we will calculate all the image like 60 360/601 = 5 then it will be 15 and we won't say any image is imposed to other right ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there are certain angles at which imposition occurs like 30, 60 90 but if we talk about 33.45 there might not be an imposition , but still there is possibility

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok but how u knew that they will be only two ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is there any princible for that ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is what i studied ages ago lol, sorry for that and still i remember you can look up in articles on google you will get to know a lot i am sure

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i say 7 with 90 % :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ghazi what about this explanation Images I1 and I2 are primary images formed by the two plane mirrors. Image I3 was found by reflecting image I2 across the extension of the top mirror. And image I4 was found by reflecting the image I1 across the side mirror.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ghazi i think now am 99.99% as let's say three images one on each mirror and three others one on each crease and the last one at the point where they all meet then they r 7 do u agree with that ??
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