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baldymcgee6
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@hartnn, @klimenkov

baldymcgee6
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dw:1351711571629:dw

hartnn
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ok, d2y/dx^2 = d/dx (cot t) , right ?
d/dx (cot t) = d/dt(cot t) * dt/dx
and u know dt/dx from dx/dt

klimenkov
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By what parameter you want to differentiate cot?

hartnn
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i think x, isn't it ?

baldymcgee6
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dw:1351712169898:dw

hartnn
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u got what i did ?

baldymcgee6
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when t = pi/4

baldymcgee6
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I'm still confused how you got d/dt(cot t) * dt/dx

hartnn
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dw:1351712487011:dw

hartnn
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\(\huge \frac{d}{dx}f(t)=\frac{d}{dt}f(t) \frac{dt}{dx}\)

baldymcgee6
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oohhh.. okay... so we can write:dw:1351712793765:dw

baldymcgee6
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dw:1351712929460:dw

hartnn
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seems correct, now u can put t=pi/4

baldymcgee6
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dw:1351713083407:dw

hartnn
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yup.

baldymcgee6
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hmmmm... okay thanks so much for the help... you're the best!

hartnn
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not really...
welcome ^_^

baldymcgee6
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i am still a little bit confused how this works: d/dx (cot t) = d/dt(cot t) * dt/dx
but I will just have to study a bit more