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Derivatives of parametric curves: http://screencast.com/t/x5c5hBqr
 one year ago
 one year ago
Derivatives of parametric curves: http://screencast.com/t/x5c5hBqr
 one year ago
 one year ago

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baldymcgee6Best ResponseYou've already chosen the best response.1
@hartnn, @klimenkov
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351711571629:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, d2y/dx^2 = d/dx (cot t) , right ? d/dx (cot t) = d/dt(cot t) * dt/dx and u know dt/dx from dx/dt
 one year ago

klimenkovBest ResponseYou've already chosen the best response.0
By what parameter you want to differentiate cot?
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351712169898:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
I'm still confused how you got d/dt(cot t) * dt/dx
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\huge \frac{d}{dx}f(t)=\frac{d}{dt}f(t) \frac{dt}{dx}\)
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
oohhh.. okay... so we can write:dw:1351712793765:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351712929460:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
seems correct, now u can put t=pi/4
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351713083407:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
hmmmm... okay thanks so much for the help... you're the best!
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
not really... welcome ^_^
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
i am still a little bit confused how this works: d/dx (cot t) = d/dt(cot t) * dt/dx but I will just have to study a bit more
 one year ago
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