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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351711571629:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, d2y/dx^2 = d/dx (cot t) , right ? d/dx (cot t) = d/dt(cot t) * dt/dx and u know dt/dx from dx/dt

klimenkov
 3 years ago
Best ResponseYou've already chosen the best response.0By what parameter you want to differentiate cot?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351712169898:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm still confused how you got d/dt(cot t) * dt/dx

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\huge \frac{d}{dx}f(t)=\frac{d}{dt}f(t) \frac{dt}{dx}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oohhh.. okay... so we can write:dw:1351712793765:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351712929460:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1seems correct, now u can put t=pi/4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351713083407:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmmmm... okay thanks so much for the help... you're the best!

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1not really... welcome ^_^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am still a little bit confused how this works: d/dx (cot t) = d/dt(cot t) * dt/dx but I will just have to study a bit more
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