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baldymcgee6
Group Title
Derivatives of parametric curves: http://screencast.com/t/x5c5hBqr
 2 years ago
 2 years ago
baldymcgee6 Group Title
Derivatives of parametric curves: http://screencast.com/t/x5c5hBqr
 2 years ago
 2 years ago

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baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
@hartnn, @klimenkov
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
dw:1351711571629:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, d2y/dx^2 = d/dx (cot t) , right ? d/dx (cot t) = d/dt(cot t) * dt/dx and u know dt/dx from dx/dt
 2 years ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
By what parameter you want to differentiate cot?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think x, isn't it ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
dw:1351712169898:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u got what i did ?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
when t = pi/4
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
I'm still confused how you got d/dt(cot t) * dt/dx
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1351712487011:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\huge \frac{d}{dx}f(t)=\frac{d}{dt}f(t) \frac{dt}{dx}\)
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
oohhh.. okay... so we can write:dw:1351712793765:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
dw:1351712929460:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
seems correct, now u can put t=pi/4
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
dw:1351713083407:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
hmmmm... okay thanks so much for the help... you're the best!
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
not really... welcome ^_^
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.1
i am still a little bit confused how this works: d/dx (cot t) = d/dt(cot t) * dt/dx but I will just have to study a bit more
 2 years ago
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