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roselin

  • 3 years ago

find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x-2x^2 , (1,-1)

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  1. NickR
    • 3 years ago
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    start by solving for the slope of the equation

  2. roselin
    • 3 years ago
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    okay

  3. NickR
    • 3 years ago
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    do you know how to do that?

  4. roselin
    • 3 years ago
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    i have to use this formula: y=mx+b?

  5. roselin
    • 3 years ago
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    or y2-y1/ x2-x1?

  6. roselin
    • 3 years ago
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    x= 1?

  7. NickR
    • 3 years ago
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    ok so now use the formula (y-y1)=m(x-x1) where (x1,y1)=(1,-1)

  8. roselin
    • 3 years ago
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    slope=1?

  9. NickR
    • 3 years ago
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    no your slope will be m

  10. NickR
    • 3 years ago
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    yes sorry

  11. roselin
    • 3 years ago
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    using that equation i get y= mx-2

  12. NickR
    • 3 years ago
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    so y=x-2

  13. roselin
    • 3 years ago
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    okay,

  14. NickR
    • 3 years ago
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    now we need to find the inverse of the line

  15. NickR
    • 3 years ago
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    wait are you sure that you wrote the initial equation right because that is a hyperbola

  16. roselin
    • 3 years ago
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    let me check again

  17. NickR
    • 3 years ago
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    ok

  18. roselin
    • 3 years ago
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    it's y= mx-2

  19. NickR
    • 3 years ago
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    for the origional equation f(x)=x-2x^2

  20. roselin
    • 3 years ago
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    yes, its correct

  21. NickR
    • 3 years ago
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    ok well either way now we need to find the equation of a tangent line

  22. roselin
    • 3 years ago
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    how do I that?

  23. NickR
    • 3 years ago
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    1 sec g2g take a quiz b back in 10

  24. roselin
    • 3 years ago
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    okay,np

  25. NickR
    • 3 years ago
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    hmm after thinking about it i think i might have done this wrong

  26. NickR
    • 3 years ago
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    brb

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