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roselin
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find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph
f(x)=x2x^2 , (1,1)
 2 years ago
 2 years ago
roselin Group Title
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x2x^2 , (1,1)
 2 years ago
 2 years ago

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NickR Group TitleBest ResponseYou've already chosen the best response.0
start by solving for the slope of the equation
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
do you know how to do that?
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
i have to use this formula: y=mx+b?
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
or y2y1/ x2x1?
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
ok so now use the formula (yy1)=m(xx1) where (x1,y1)=(1,1)
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
no your slope will be m
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
using that equation i get y= mx2
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
now we need to find the inverse of the line
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
wait are you sure that you wrote the initial equation right because that is a hyperbola
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
let me check again
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
it's y= mx2
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
for the origional equation f(x)=x2x^2
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
yes, its correct
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
ok well either way now we need to find the equation of a tangent line
 2 years ago

roselin Group TitleBest ResponseYou've already chosen the best response.0
how do I that?
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
1 sec g2g take a quiz b back in 10
 2 years ago

NickR Group TitleBest ResponseYou've already chosen the best response.0
hmm after thinking about it i think i might have done this wrong
 2 years ago
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