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find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x-2x^2 , (1,-1)

Mathematics
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start by solving for the slope of the equation
okay
do you know how to do that?

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Other answers:

i have to use this formula: y=mx+b?
or y2-y1/ x2-x1?
x= 1?
ok so now use the formula (y-y1)=m(x-x1) where (x1,y1)=(1,-1)
slope=1?
no your slope will be m
yes sorry
using that equation i get y= mx-2
so y=x-2
okay,
now we need to find the inverse of the line
wait are you sure that you wrote the initial equation right because that is a hyperbola
let me check again
ok
it's y= mx-2
for the origional equation f(x)=x-2x^2
yes, its correct
ok well either way now we need to find the equation of a tangent line
how do I that?
1 sec g2g take a quiz b back in 10
okay,np
hmm after thinking about it i think i might have done this wrong
brb

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