## roselin 3 years ago find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x-2x^2 , (1,-1)

1. NickR

start by solving for the slope of the equation

2. roselin

okay

3. NickR

do you know how to do that?

4. roselin

i have to use this formula: y=mx+b?

5. roselin

or y2-y1/ x2-x1?

6. roselin

x= 1?

7. NickR

ok so now use the formula (y-y1)=m(x-x1) where (x1,y1)=(1,-1)

8. roselin

slope=1?

9. NickR

no your slope will be m

10. NickR

yes sorry

11. roselin

using that equation i get y= mx-2

12. NickR

so y=x-2

13. roselin

okay,

14. NickR

now we need to find the inverse of the line

15. NickR

wait are you sure that you wrote the initial equation right because that is a hyperbola

16. roselin

let me check again

17. NickR

ok

18. roselin

it's y= mx-2

19. NickR

for the origional equation f(x)=x-2x^2

20. roselin

yes, its correct

21. NickR

ok well either way now we need to find the equation of a tangent line

22. roselin

how do I that?

23. NickR

1 sec g2g take a quiz b back in 10

24. roselin

okay,np

25. NickR

hmm after thinking about it i think i might have done this wrong

26. NickR

brb