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start by solving for the slope of the equation

okay

do you know how to do that?

i have to use this formula: y=mx+b?

or y2-y1/ x2-x1?

x= 1?

ok so now use the formula (y-y1)=m(x-x1)
where (x1,y1)=(1,-1)

slope=1?

no your slope will be m

yes sorry

using that equation i get y= mx-2

so y=x-2

okay,

now we need to find the inverse of the line

wait are you sure that you wrote the initial equation right because that is a hyperbola

let me check again

ok

it's y= mx-2

for the origional equation f(x)=x-2x^2

yes, its correct

ok well either way now we need to find the equation of a tangent line

how do I that?

1 sec g2g take a quiz b back in 10

okay,np

hmm after thinking about it i think i might have done this wrong

brb