roselin
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph
f(x)=x2x^2 , (1,1)



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NickR
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start by solving for the slope of the equation

roselin
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okay

NickR
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do you know how to do that?

roselin
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i have to use this formula: y=mx+b?

roselin
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or y2y1/ x2x1?

roselin
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x= 1?

NickR
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ok so now use the formula (yy1)=m(xx1)
where (x1,y1)=(1,1)

roselin
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slope=1?

NickR
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no your slope will be m

NickR
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yes sorry

roselin
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using that equation i get y= mx2

NickR
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so y=x2

roselin
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okay,

NickR
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now we need to find the inverse of the line

NickR
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wait are you sure that you wrote the initial equation right because that is a hyperbola

roselin
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let me check again

NickR
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ok

roselin
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it's y= mx2

NickR
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for the origional equation f(x)=x2x^2

roselin
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yes, its correct

NickR
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ok well either way now we need to find the equation of a tangent line

roselin
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how do I that?

NickR
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1 sec g2g take a quiz b back in 10

roselin
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okay,np

NickR
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hmm after thinking about it i think i might have done this wrong

NickR
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brb