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find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph
f(x)=x2x^2 , (1,1)
 one year ago
 one year ago
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x2x^2 , (1,1)
 one year ago
 one year ago

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NickRBest ResponseYou've already chosen the best response.0
start by solving for the slope of the equation
 one year ago

NickRBest ResponseYou've already chosen the best response.0
do you know how to do that?
 one year ago

roselinBest ResponseYou've already chosen the best response.0
i have to use this formula: y=mx+b?
 one year ago

NickRBest ResponseYou've already chosen the best response.0
ok so now use the formula (yy1)=m(xx1) where (x1,y1)=(1,1)
 one year ago

roselinBest ResponseYou've already chosen the best response.0
using that equation i get y= mx2
 one year ago

NickRBest ResponseYou've already chosen the best response.0
now we need to find the inverse of the line
 one year ago

NickRBest ResponseYou've already chosen the best response.0
wait are you sure that you wrote the initial equation right because that is a hyperbola
 one year ago

NickRBest ResponseYou've already chosen the best response.0
for the origional equation f(x)=x2x^2
 one year ago

NickRBest ResponseYou've already chosen the best response.0
ok well either way now we need to find the equation of a tangent line
 one year ago

NickRBest ResponseYou've already chosen the best response.0
1 sec g2g take a quiz b back in 10
 one year ago

NickRBest ResponseYou've already chosen the best response.0
hmm after thinking about it i think i might have done this wrong
 one year ago
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