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anonymous
 4 years ago
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph
f(x)=x2x^2 , (1,1)
anonymous
 4 years ago
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x2x^2 , (1,1)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0start by solving for the slope of the equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know how to do that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to use this formula: y=mx+b?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so now use the formula (yy1)=m(xx1) where (x1,y1)=(1,1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no your slope will be m

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0using that equation i get y= mx2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now we need to find the inverse of the line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait are you sure that you wrote the initial equation right because that is a hyperbola

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for the origional equation f(x)=x2x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok well either way now we need to find the equation of a tangent line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 sec g2g take a quiz b back in 10

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm after thinking about it i think i might have done this wrong
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