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roselin

find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x-2x^2 , (1,-1)

  • one year ago
  • one year ago

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  1. NickR
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    start by solving for the slope of the equation

    • one year ago
  2. roselin
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    okay

    • one year ago
  3. NickR
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    do you know how to do that?

    • one year ago
  4. roselin
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    i have to use this formula: y=mx+b?

    • one year ago
  5. roselin
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    or y2-y1/ x2-x1?

    • one year ago
  6. roselin
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    x= 1?

    • one year ago
  7. NickR
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    ok so now use the formula (y-y1)=m(x-x1) where (x1,y1)=(1,-1)

    • one year ago
  8. roselin
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    slope=1?

    • one year ago
  9. NickR
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    no your slope will be m

    • one year ago
  10. NickR
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    yes sorry

    • one year ago
  11. roselin
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    using that equation i get y= mx-2

    • one year ago
  12. NickR
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    so y=x-2

    • one year ago
  13. roselin
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    okay,

    • one year ago
  14. NickR
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    now we need to find the inverse of the line

    • one year ago
  15. NickR
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    wait are you sure that you wrote the initial equation right because that is a hyperbola

    • one year ago
  16. roselin
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    let me check again

    • one year ago
  17. NickR
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    ok

    • one year ago
  18. roselin
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    it's y= mx-2

    • one year ago
  19. NickR
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    for the origional equation f(x)=x-2x^2

    • one year ago
  20. roselin
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    yes, its correct

    • one year ago
  21. NickR
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    ok well either way now we need to find the equation of a tangent line

    • one year ago
  22. roselin
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    how do I that?

    • one year ago
  23. NickR
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    1 sec g2g take a quiz b back in 10

    • one year ago
  24. roselin
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    okay,np

    • one year ago
  25. NickR
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    hmm after thinking about it i think i might have done this wrong

    • one year ago
  26. NickR
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    brb

    • one year ago
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