anonymous
  • anonymous
find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph f(x)=x-2x^2 , (1,-1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
start by solving for the slope of the equation
anonymous
  • anonymous
okay
anonymous
  • anonymous
do you know how to do that?

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anonymous
  • anonymous
i have to use this formula: y=mx+b?
anonymous
  • anonymous
or y2-y1/ x2-x1?
anonymous
  • anonymous
x= 1?
anonymous
  • anonymous
ok so now use the formula (y-y1)=m(x-x1) where (x1,y1)=(1,-1)
anonymous
  • anonymous
slope=1?
anonymous
  • anonymous
no your slope will be m
anonymous
  • anonymous
yes sorry
anonymous
  • anonymous
using that equation i get y= mx-2
anonymous
  • anonymous
so y=x-2
anonymous
  • anonymous
okay,
anonymous
  • anonymous
now we need to find the inverse of the line
anonymous
  • anonymous
wait are you sure that you wrote the initial equation right because that is a hyperbola
anonymous
  • anonymous
let me check again
anonymous
  • anonymous
ok
anonymous
  • anonymous
it's y= mx-2
anonymous
  • anonymous
for the origional equation f(x)=x-2x^2
anonymous
  • anonymous
yes, its correct
anonymous
  • anonymous
ok well either way now we need to find the equation of a tangent line
anonymous
  • anonymous
how do I that?
anonymous
  • anonymous
1 sec g2g take a quiz b back in 10
anonymous
  • anonymous
okay,np
anonymous
  • anonymous
hmm after thinking about it i think i might have done this wrong
anonymous
  • anonymous
brb

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