## BrennaM Group Title Quadratic Expressions 2 years ago 2 years ago

1. BrennaM

2. jazy

Your equation is:$-\frac{1 }{ 2 }x^2- 2x-6$Use the Quadratic formula:$x = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2a }$ Fill in the values: $-(-2) \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}$ $2 \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}$ -2^2 = 4 4(-1/2)(-6) = 12 1 * -1/2$2\pm \frac{\sqrt{4 - 12} }{ -1 }$$2 \pm \frac{ \sqrt{-8} }{ -1 }$$2\pm \frac{ 2.83 }{ -1 }$$2\pm -2.38$ 2 + (-2.38) = -0.37 2 - (-2.38) = 2 + 2.38 = 4.38 So the two solutions for x are: x = -0.37 and x = 4.38

3. jazy

@BrennaM I hope this helps! (:

4. BrennaM

Thanks it did :)