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BrennaM

  • 3 years ago

Quadratic Expressions

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  1. BrennaM
    • 3 years ago
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  2. jazy
    • 3 years ago
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    Your equation is:\[-\frac{1 }{ 2 }x^2- 2x-6\]Use the Quadratic formula:\[x = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2a }\] Fill in the values: \[-(-2) \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}\] \[2 \pm \frac{ \sqrt{-2^2 - 4(-\frac{ 1 }{ 2 })(-6)} }{ 2(-\frac{ 1 }{ 2 })}\] -2^2 = 4 4(-1/2)(-6) = 12 1 * -1/2\[2\pm \frac{\sqrt{4 - 12} }{ -1 }\]\[2 \pm \frac{ \sqrt{-8} }{ -1 }\]\[2\pm \frac{ 2.83 }{ -1 }\]\[2\pm -2.38\] 2 + (-2.38) = -0.37 2 - (-2.38) = 2 + 2.38 = 4.38 So the two solutions for x are: x = -0.37 and x = 4.38

  3. jazy
    • 3 years ago
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    @BrennaM I hope this helps! (:

  4. BrennaM
    • 3 years ago
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    Thanks it did :)

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