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jazyBest ResponseYou've already chosen the best response.1
Your equation is:\[\frac{1 }{ 2 }x^2 2x6\]Use the Quadratic formula:\[x = b \pm \frac{ \sqrt{b^2  4ac} }{ 2a }\] Fill in the values: \[(2) \pm \frac{ \sqrt{2^2  4(\frac{ 1 }{ 2 })(6)} }{ 2(\frac{ 1 }{ 2 })}\] \[2 \pm \frac{ \sqrt{2^2  4(\frac{ 1 }{ 2 })(6)} }{ 2(\frac{ 1 }{ 2 })}\] 2^2 = 4 4(1/2)(6) = 12 1 * 1/2\[2\pm \frac{\sqrt{4  12} }{ 1 }\]\[2 \pm \frac{ \sqrt{8} }{ 1 }\]\[2\pm \frac{ 2.83 }{ 1 }\]\[2\pm 2.38\] 2 + (2.38) = 0.37 2  (2.38) = 2 + 2.38 = 4.38 So the two solutions for x are: x = 0.37 and x = 4.38
 one year ago

jazyBest ResponseYou've already chosen the best response.1
@BrennaM I hope this helps! (:
 one year ago
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