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I want to check myself on this one:
a/2 + 1/4 divided by a/3  1/2
you need same denominator so you multiply a/2 by 2 which gives you 2a/4 + 1/4 = 3a/4.
Next part a/3  1/2 so you multiply a/3 by 2 to get 2a/6 then 1/2 you multiply by 3 to get 3/6 so
2a/6  3/6 = 2a3/6. Now 3a/4 divided by 2a3/6 then you use the reciprocal and multiply 3a/4 * 6/3 to get a/2 (after you reduce and cancel out like terms)?
 one year ago
 one year ago
I want to check myself on this one: a/2 + 1/4 divided by a/3  1/2 you need same denominator so you multiply a/2 by 2 which gives you 2a/4 + 1/4 = 3a/4. Next part a/3  1/2 so you multiply a/3 by 2 to get 2a/6 then 1/2 you multiply by 3 to get 3/6 so 2a/6  3/6 = 2a3/6. Now 3a/4 divided by 2a3/6 then you use the reciprocal and multiply 3a/4 * 6/3 to get a/2 (after you reduce and cancel out like terms)?
 one year ago
 one year ago

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asnaseerBest ResponseYou've already chosen the best response.1
your 1st step has an error:\[\frac{a}{2}+\frac{1}{4}=\frac{2a}{4}+\frac{1}{4}\ne\frac{3a}{4}\]
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
do you understand why?
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
Not sure .. now I'm confused LOL
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
look at the numerators of that fraction: 2a + 1 = ?
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
it would just be 2a + 1 / 4
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
because 2a and 1 are separate
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
So then it would be 2a + 1/4 divided by 2a  3 / 6
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
your 2nd step was correct:\[\frac{a}{3}\frac{1}{2}=\frac{2a3}{6}\]
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
your 3rd step has an error
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
then 2a + 1 / 4 * 6 / 2a  3
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
what you want is:\[\frac{2a+1}{4}\div\frac{2a3}{6}=\frac{2a+1}{4}\times\frac{6}{2a3}\]yes  you have it right now :)
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
yea I saw my error from the first part and realized I made the same mistake and then corrected it
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
ok  so you know what to do now and understand the process?
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
Now I am unsure of the rest ...
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
:) np  just let me know what part is troubling you...
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
you cannot do anything with the 2a + 1 or the 2a  3 because the 2a's are attached to something, so the only thing you can mess with are the 4 and 6, correct?
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
(2a + 1)*3 / 2*(2a  3) = 6a + 3 / 4a  6 ?
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
that is correct. although I would leave it in the form:\[\frac{3(2a+1)}{2(2a3)}\]
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
haha yea i just noticed it was already reduced and doing what I did, UNreduced it LOL
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
gr8! the good thing is that you recognised your mistakes  which is vital if you want to improve! :D
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
I second guess myself all the time and change things when they don't need changed or overthink it!
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
he he  don't worry too much about it  the main thing here is that you have a good "hunger" for knowledge which means you will go far my friend! :D
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
thanks for your help! (I haven't "mathed" in about 10 years gosh, that probably gives away my age) I'm a college student again and I'm taking Technical Algebra ... I actually like math now! =)
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
I left college many many moons ago  oh no!  now I've given away my age as well :) Like you, I still have a thirst for knowledge. :D
 one year ago

puddlebunnyBest ResponseYou've already chosen the best response.1
You're as "young" as you feel! take care and have a blessed day =) =)
 one year ago

asnaseerBest ResponseYou've already chosen the best response.1
thx  you too my friend! :)
 one year ago
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