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 2 years ago
I want to check myself on this one:
a/2 + 1/4 divided by a/3  1/2
you need same denominator so you multiply a/2 by 2 which gives you 2a/4 + 1/4 = 3a/4.
Next part a/3  1/2 so you multiply a/3 by 2 to get 2a/6 then 1/2 you multiply by 3 to get 3/6 so
2a/6  3/6 = 2a3/6. Now 3a/4 divided by 2a3/6 then you use the reciprocal and multiply 3a/4 * 6/3 to get a/2 (after you reduce and cancel out like terms)?
 2 years ago
I want to check myself on this one: a/2 + 1/4 divided by a/3  1/2 you need same denominator so you multiply a/2 by 2 which gives you 2a/4 + 1/4 = 3a/4. Next part a/3  1/2 so you multiply a/3 by 2 to get 2a/6 then 1/2 you multiply by 3 to get 3/6 so 2a/6  3/6 = 2a3/6. Now 3a/4 divided by 2a3/6 then you use the reciprocal and multiply 3a/4 * 6/3 to get a/2 (after you reduce and cancel out like terms)?

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asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1your 1st step has an error:\[\frac{a}{2}+\frac{1}{4}=\frac{2a}{4}+\frac{1}{4}\ne\frac{3a}{4}\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1do you understand why?

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1Not sure .. now I'm confused LOL

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1look at the numerators of that fraction: 2a + 1 = ?

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1it would just be 2a + 1 / 4

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1because 2a and 1 are separate

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1So then it would be 2a + 1/4 divided by 2a  3 / 6

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1your 2nd step was correct:\[\frac{a}{3}\frac{1}{2}=\frac{2a3}{6}\]

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1your 3rd step has an error

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1then 2a + 1 / 4 * 6 / 2a  3

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1what you want is:\[\frac{2a+1}{4}\div\frac{2a3}{6}=\frac{2a+1}{4}\times\frac{6}{2a3}\]yes  you have it right now :)

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1yea I saw my error from the first part and realized I made the same mistake and then corrected it

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1ok  so you know what to do now and understand the process?

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1Now I am unsure of the rest ...

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1:) np  just let me know what part is troubling you...

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1you cannot do anything with the 2a + 1 or the 2a  3 because the 2a's are attached to something, so the only thing you can mess with are the 4 and 6, correct?

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1(2a + 1)*3 / 2*(2a  3) = 6a + 3 / 4a  6 ?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1that is correct. although I would leave it in the form:\[\frac{3(2a+1)}{2(2a3)}\]

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1haha yea i just noticed it was already reduced and doing what I did, UNreduced it LOL

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1gr8! the good thing is that you recognised your mistakes  which is vital if you want to improve! :D

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1I second guess myself all the time and change things when they don't need changed or overthink it!

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1he he  don't worry too much about it  the main thing here is that you have a good "hunger" for knowledge which means you will go far my friend! :D

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1thanks for your help! (I haven't "mathed" in about 10 years gosh, that probably gives away my age) I'm a college student again and I'm taking Technical Algebra ... I actually like math now! =)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1I left college many many moons ago  oh no!  now I've given away my age as well :) Like you, I still have a thirst for knowledge. :D

puddlebunny
 2 years ago
Best ResponseYou've already chosen the best response.1You're as "young" as you feel! take care and have a blessed day =) =)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.1thx  you too my friend! :)
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