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hawkfalcon

  • 3 years ago

A function f is defined on the interval [0,4], and its derivative is f'(x)=e^sinx - 2cos3x On what interval is f increasing? At what values of x does f have a local maxima? How many points of inflection does the graph of f have?

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  1. hawkfalcon
    • 3 years ago
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    \[f'(x)=e ^{sinx} - 2\cos3x\]

  2. Jonask
    • 3 years ago
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    when is \[f'(x)>0\]solve

  3. Jonask
    • 3 years ago
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    \[e^{\sin x}>2\cos 3x\] \[\sin x>\ln(2\cos 3x)\]

  4. hawkfalcon
    • 3 years ago
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    Okay. O.o

  5. mahmit2012
    • 3 years ago
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    |dw:1351732431643:dw|

  6. hawkfalcon
    • 3 years ago
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    Inequalities? :3 Is there a way you can do it without that? /me never learned about inequalities

  7. hawkfalcon
    • 3 years ago
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    @mahmit2012 Alright. :/

  8. Jonask
    • 3 years ago
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    @mahmit2012 is giving you a good method

  9. hawkfalcon
    • 3 years ago
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    Critical points?:3

  10. hawkfalcon
    • 3 years ago
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    @mahmit2012 How would I find those points?

  11. mahmit2012
    • 3 years ago
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    You should find the critical points with Matlab or other software .

  12. hawkfalcon
    • 3 years ago
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    Alright. And that will show me the ranges? :) Thanks!

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