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\[f'(x)=e ^{sinx} - 2\cos3x\]

when is \[f'(x)>0\]solve

\[e^{\sin x}>2\cos 3x\]
\[\sin x>\ln(2\cos 3x)\]

Okay. O.o

|dw:1351732431643:dw|

Inequalities? :3
Is there a way you can do it without that? /me never learned about inequalities

@mahmit2012
Alright. :/

@mahmit2012 is giving you a good method

Critical points?:3

@mahmit2012
How would I find those points?

You should find the critical points with Matlab or other software .

Alright.
And that will show me the ranges? :) Thanks!