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lilsis76
Group Title
graph each point in a polar coordinate system then convert the given polar coordinates to rectangluar coordinates.
can someone help me do this step by step so i understand please.
1) a) (3, 2pi/3)
 one year ago
 one year ago
lilsis76 Group Title
graph each point in a polar coordinate system then convert the given polar coordinates to rectangluar coordinates. can someone help me do this step by step so i understand please. 1) a) (3, 2pi/3)
 one year ago
 one year ago

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ByteMe Group TitleBest ResponseYou've already chosen the best response.1
dw:1351734596209:dw notice that the point will have a negative x, positive y coordinates...
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
why would it be negative?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
use... \(\large x=rcos\theta \) \(\large y=rsin\theta \)
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
because the point is in the second quadrant....
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
dw:1351734804583:dw
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay so r is the radius, and the radius is 3.
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351734929718:dw2pi/3....i dont see how that can be at that angle.
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
yes... r=3; \(\theta=\frac{2\pi}{3} \)
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay i see that .....
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
dw:1351735004666:dw
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
but shouldnt the 2pi/3 go on the bottom like in the 270 degree? ugh...or do i use calcutore to solve?
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
oh lol sorry, i got them mixed up
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
and why is it to the left of the graph? arent they positive?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
dw:1351735188538:dw
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
what are you asking in your last post?
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay, u see how u found the point in the left of the graph chart, why is it to the left. isnt it (  , +) we have a (+,+)
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
do u get what i mean? cuz i see a positive point
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
oh... you're referring to the point \(\large (3, \frac{2\pi}{3}) \)..... that point is represented in POLAR form, \(\large (r, \theta) \) and not cartesian form (x, y)
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351735526253:dw
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay but why doesnt the 3 go to the right?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
3 is your radius... NOT your x coordinate...
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
here... click on this link... http://www.mathwords.com/p/polar_rectangular_conversion_formulas.htm
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay then, so looking at the unit circle its the point then, and like u said the 3 is the radius. so thats the reason why its to the left. It says now to convert the given polar coordinates to rectangular coordinates
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
how would i start this one?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
no... the reason why it's on the left of the yaxis is because the angle theta, 2pi/3 resides in the second quadrant.
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
here... this is a better explanation of polar coordinates: http://www.mathsisfun.com/polarcartesiancoordinates.html
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay ill look at it
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
so those formulas i gave you converts the given point in POLAR form to RECTANGULAR form...
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
okay. let me try on here and u let me know if i do it wrong. please.
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
x= r cos theta > 3 cos 2pi/6 > 3(1/2) > 3/2 y= r sin theta > 3 sin 2pi/6 > 3(sqrt.3 /2) > 3/2 sqrt3
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
why is the angle 2pi/6 ??? i thought it was 2pi/3 ???
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
AH! sorry, haha i was looking at a 6. let me try
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
x= r cos theta > 3 cos 2pi/3 > 3(1/2) > 3/2 y= r sin theta > 3 sin 2pi/3 > 3(sqrt.3 /2) > 3/2 sqrt3
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
careful.... \(\large cos(\frac{2\pi}{3})=\frac{1}{2} \)
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
your y coordinate is correct...
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
oops, thanks, okay so then x= r cos theta > 3 cos 2pi/6 > 3( 1/2) >  3/2 y= r sin theta > 3 sin 2pi/6 > 3(sqrt.3 /2) > 3/2 sqrt3
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
yes... so the x y coordinate for the point is \(\large (\frac{3}{2},\frac{3\sqrt3}{2}) \)
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351736659036:dw then the coordinate  3/2, 3 sqrt 3 /2 would be in the same area right?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
it is the SAME point.... only expressed in cartesian form
 one year ago

lilsis76 Group TitleBest ResponseYou've already chosen the best response.0
oh...okay, let me try the other problems and ill be back online if I need help. THANK YOU!!!
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
yw... glad i could help...
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.1
good luck... :)
 one year ago
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