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lilsis76
 3 years ago
graph each point in a polar coordinate system then convert the given polar coordinates to rectangluar coordinates.
can someone help me do this step by step so i understand please.
1) a) (3, 2pi/3)
lilsis76
 3 years ago
graph each point in a polar coordinate system then convert the given polar coordinates to rectangluar coordinates. can someone help me do this step by step so i understand please. 1) a) (3, 2pi/3)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351734596209:dw notice that the point will have a negative x, positive y coordinates...

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0why would it be negative?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use... \(\large x=rcos\theta \) \(\large y=rsin\theta \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because the point is in the second quadrant....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351734804583:dw

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay so r is the radius, and the radius is 3.

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351734929718:dw2pi/3....i dont see how that can be at that angle.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes... r=3; \(\theta=\frac{2\pi}{3} \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351735004666:dw

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0but shouldnt the 2pi/3 go on the bottom like in the 270 degree? ugh...or do i use calcutore to solve?

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0oh lol sorry, i got them mixed up

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0and why is it to the left of the graph? arent they positive?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351735188538:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what are you asking in your last post?

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay, u see how u found the point in the left of the graph chart, why is it to the left. isnt it (  , +) we have a (+,+)

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0do u get what i mean? cuz i see a positive point

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh... you're referring to the point \(\large (3, \frac{2\pi}{3}) \)..... that point is represented in POLAR form, \(\large (r, \theta) \) and not cartesian form (x, y)

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay but why doesnt the 3 go to the right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.03 is your radius... NOT your x coordinate...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here... click on this link... http://www.mathwords.com/p/polar_rectangular_conversion_formulas.htm

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay then, so looking at the unit circle its the point then, and like u said the 3 is the radius. so thats the reason why its to the left. It says now to convert the given polar coordinates to rectangular coordinates

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0how would i start this one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no... the reason why it's on the left of the yaxis is because the angle theta, 2pi/3 resides in the second quadrant.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here... this is a better explanation of polar coordinates: http://www.mathsisfun.com/polarcartesiancoordinates.html

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so those formulas i gave you converts the given point in POLAR form to RECTANGULAR form...

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay. let me try on here and u let me know if i do it wrong. please.

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0x= r cos theta > 3 cos 2pi/6 > 3(1/2) > 3/2 y= r sin theta > 3 sin 2pi/6 > 3(sqrt.3 /2) > 3/2 sqrt3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is the angle 2pi/6 ??? i thought it was 2pi/3 ???

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0AH! sorry, haha i was looking at a 6. let me try

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0x= r cos theta > 3 cos 2pi/3 > 3(1/2) > 3/2 y= r sin theta > 3 sin 2pi/3 > 3(sqrt.3 /2) > 3/2 sqrt3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0careful.... \(\large cos(\frac{2\pi}{3})=\frac{1}{2} \)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your y coordinate is correct...

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0oops, thanks, okay so then x= r cos theta > 3 cos 2pi/6 > 3( 1/2) >  3/2 y= r sin theta > 3 sin 2pi/6 > 3(sqrt.3 /2) > 3/2 sqrt3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes... so the x y coordinate for the point is \(\large (\frac{3}{2},\frac{3\sqrt3}{2}) \)

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351736659036:dw then the coordinate  3/2, 3 sqrt 3 /2 would be in the same area right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is the SAME point.... only expressed in cartesian form

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0oh...okay, let me try the other problems and ill be back online if I need help. THANK YOU!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yw... glad i could help...
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