Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
chrislb22
Group Title
Calculate the derivative of the function.
( Using Chain Rule)
f(x) = square root 5x+x^2 << all under root
 one year ago
 one year ago
chrislb22 Group Title
Calculate the derivative of the function. ( Using Chain Rule) f(x) = square root 5x+x^2 << all under root
 one year ago
 one year ago

This Question is Closed

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{d}{dx}[\sqrt{f(x)]}=\frac{f'(x)}{2\sqrt{f(x)}}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
use \(f(x)=5x+x^2,f'(x)=5+2x\) plug and be done
 one year ago

chrislb22 Group TitleBest ResponseYou've already chosen the best response.0
just plug 5+2x into which part of the equation?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Let u = 5x+x^2 \[f'(x) = \frac{d}{du}\sqrt u \times \frac{d}{dx}(5x+x^2)=...?\]
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
First, find d/du (sqrt u) Then find d/dx (5x + x^2) Next, multiply the two results Finally, replace u by 5x+x^2.
 one year ago

chrislb22 Group TitleBest ResponseYou've already chosen the best response.0
i got 2x(5x+x^2) ... is that correct? i had a bit of trouble after plugging the equation in
 one year ago

chrislb22 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{5+x^2}\times(5x+x)^2\]
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{d}{du} \sqrt u = \frac{1}{2 \sqrt u} \] \[\frac{d}{dx} (5x+x^2)= 5 + 2x\] Multiply the two results, and sub y = 5x+x^2 back to the answer you get..
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.