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\[\frac{d}{dx}[\sqrt{f(x)]}=\frac{f'(x)}{2\sqrt{f(x)}}\]

use
\(f(x)=5x+x^2,f'(x)=5+2x\) plug and be done

just plug 5+2x into which part of the equation?

Let u = 5x+x^2
\[f'(x) = \frac{d}{du}\sqrt u \times \frac{d}{dx}(5x+x^2)=...?\]

i got 2x(5x+x^2)
... is that correct? i had a bit of trouble after plugging the equation in

\[\sqrt{5+x^2}\times(5x+x)^2\]