A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Calculate the derivative of the function.
( Using Chain Rule)
f(x) = square root 5x+x^2 << all under root
anonymous
 3 years ago
Calculate the derivative of the function. ( Using Chain Rule) f(x) = square root 5x+x^2 << all under root

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}[\sqrt{f(x)]}=\frac{f'(x)}{2\sqrt{f(x)}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use \(f(x)=5x+x^2,f'(x)=5+2x\) plug and be done

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just plug 5+2x into which part of the equation?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Let u = 5x+x^2 \[f'(x) = \frac{d}{du}\sqrt u \times \frac{d}{dx}(5x+x^2)=...?\]

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0First, find d/du (sqrt u) Then find d/dx (5x + x^2) Next, multiply the two results Finally, replace u by 5x+x^2.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got 2x(5x+x^2) ... is that correct? i had a bit of trouble after plugging the equation in

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{5+x^2}\times(5x+x)^2\]

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{du} \sqrt u = \frac{1}{2 \sqrt u} \] \[\frac{d}{dx} (5x+x^2)= 5 + 2x\] Multiply the two results, and sub y = 5x+x^2 back to the answer you get..
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.