baldymcgee6
  • baldymcgee6
Partial Derivatives... posted below
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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baldymcgee6
  • baldymcgee6
|dw:1351748975295:dw|
hartnn
  • hartnn
partial derivative means u treat other variable as constant. u know this ?
baldymcgee6
  • baldymcgee6
Right, so we treat y as a constant in the first one..

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anonymous
  • anonymous
Which variable are you taking constant>?
hartnn
  • hartnn
yes.
baldymcgee6
  • baldymcgee6
|dw:1351749134665:dw|
hartnn
  • hartnn
absolutely! that was my next statement, that u need log diff. here.
baldymcgee6
  • baldymcgee6
In my experiences with log diff I always had a function in the form of y = f(x)^g(x).... So what do we do here?
baldymcgee6
  • baldymcgee6
do we write y = ......?
hartnn
  • hartnn
taking log on both sides, u get log y = g(x) log f(x) then use product rule
hartnn
  • hartnn
u'll also need a chain rule for this....
baldymcgee6
  • baldymcgee6
|dw:1351749340629:dw|
hartnn
  • hartnn
oh dear! the y on left and on right are different, u should have used g or some other letter
baldymcgee6
  • baldymcgee6
oohhhhhh.. that's where I went wrong... this is off my last quiz :/
baldymcgee6
  • baldymcgee6
so it'll be g'/g on the left?
hartnn
  • hartnn
yes, after doing product rule , u resubstitute for g
baldymcgee6
  • baldymcgee6
|dw:1351749800366:dw|
hartnn
  • hartnn
thats right
baldymcgee6
  • baldymcgee6
|dw:1351749846652:dw|
hartnn
  • hartnn
absolutely correct
hartnn
  • hartnn
same for 2nd question, just replace x with y and y with x
baldymcgee6
  • baldymcgee6
right... I just messed up on calling the function y... messed with my head.
baldymcgee6
  • baldymcgee6
thanks again for the insight!
baldymcgee6
  • baldymcgee6
I'm not going to do the second derivative, I think I can get it... Thanks so much!
baldymcgee6
  • baldymcgee6
I mean, i'm not going to do it on here.. :)
hartnn
  • hartnn
ok, welcome ^_^

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