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baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
Do you know what rational means?
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1351750351911:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1351750674780:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
But what does it equal as a rational exponent?
 one year ago

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dw:1351751110425:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1351751331010:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1351751362625:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
dw:1351751464943:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
It's fine, the original question states: Create your own term using a rational exponent and then convert it to a radical expression. Explain, in complete sentences, how the expression was converted. You created the term cbrt(27), they want yo to be able to convert to rational exponents, so 27^(1/3) Then just explain how you converted it.
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
cube root
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
sqrt > square root cbrt > cube root
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
Yes it works... the cube root of 27. Just say in words how you would convert from a rational exponent to a radical.
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.2
I gottta go to bed... :( i think you can handle the rest?? It's not a formula, its just the degree of the radical goes to the denominator of the rational exponent, and the degree of the radicand goes to the numerator of the rational exponent. http://www.purplemath.com/modules/exponent5.htm
 one year ago
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