## chrislb22 Group Title Calculate the derivative of the function. Use Chain Rule g(z) = (z^2/7+z)^2 one year ago one year ago

1. baldymcgee6 Group Title

Can you set it up?

2. chrislb22 Group Title

im guessing its 2(z^2) x 2(7)

3. baldymcgee6 Group Title

|dw:1351750568965:dw|Is this the function?

4. chrislb22 Group Title

@baldymcgee6 yes, and @sirm3d no the Z is squared

5. sirm3d Group Title

sorry i mistyped

6. chrislb22 Group Title

yea i just have a hard time with this one. maybe because its a different format

7. sirm3d Group Title

the first part is differentiating the square

8. sirm3d Group Title

$2\left( \frac{ z^{2} }{ 7+z } \right)$

9. baldymcgee6 Group Title

There is an easier method if you want..

10. baldymcgee6 Group Title

|dw:1351750799134:dw|Just use the power rule and chain rule throughout, no need for quotient rule.

11. sirm3d Group Title

the second part is where the chain rule is used. Get the derivative of $\frac{ z^{2} }{ 7+z }$ by the quotient rule for differentiation

12. baldymcgee6 Group Title

|dw:1351750960037:dw|

13. baldymcgee6 Group Title

You will actually need the product rule because the co-efficient is a variable.

14. chrislb22 Group Title

@sirm3d so the derivative would be 2x/7 ?and @baldymcgee6 so the previous equation you typed is the product rule? or chain?

15. sirm3d Group Title

nope. the quotient rule on $\frac{ z^{2} }{ 7+z }$ will produce $\frac{ \left( 7+z \right)\left( 2z \right)-\left( z^{2}\left( 1 \right) \right) }{ \left( 7+z \right)^{2} }$

16. baldymcgee6 Group Title

|dw:1351751195729:dw|

17. chrislb22 Group Title

@baldymcgee6 quick question. where did u get (-1) in the very first step in the equation

18. baldymcgee6 Group Title

|dw:1351751807412:dw|

19. chrislb22 Group Title

yes

20. baldymcgee6 Group Title

|dw:1351751909040:dw|

21. chrislb22 Group Title

also the second step the last part of the equation is cut off -2(7+z....

22. baldymcgee6 Group Title

sorry, my drawings keep getting cut off for some reason. -2(7+z)^-3 Just using power rule there.

23. chrislb22 Group Title

awesome, thanks a lot

24. baldymcgee6 Group Title

Welcome =D