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- anonymous

Calculate the derivative of the function.
Use Chain Rule
g(z) = (z^2/7+z)^2

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- anonymous

Calculate the derivative of the function.
Use Chain Rule
g(z) = (z^2/7+z)^2

- schrodinger

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- baldymcgee6

Can you set it up?

- anonymous

im guessing its 2(z^2) x 2(7)

- baldymcgee6

|dw:1351750568965:dw|Is this the function?

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- anonymous

@baldymcgee6 yes, and @sirm3d no the Z is squared

- sirm3d

sorry i mistyped

- anonymous

yea i just have a hard time with this one. maybe because its a different format

- sirm3d

the first part is differentiating the square

- sirm3d

\[2\left( \frac{ z^{2} }{ 7+z } \right)\]

- baldymcgee6

There is an easier method if you want..

- baldymcgee6

|dw:1351750799134:dw|Just use the power rule and chain rule throughout, no need for quotient rule.

- sirm3d

the second part is where the chain rule is used. Get the derivative of \[\frac{ z^{2} }{ 7+z }\] by the quotient rule for differentiation

- baldymcgee6

|dw:1351750960037:dw|

- baldymcgee6

You will actually need the product rule because the co-efficient is a variable.

- anonymous

@sirm3d so the derivative would be 2x/7 ?and @baldymcgee6 so the previous equation you typed is the product rule? or chain?

- sirm3d

nope. the quotient rule on \[\frac{ z^{2} }{ 7+z }\] will produce
\[\frac{ \left( 7+z \right)\left( 2z \right)-\left( z^{2}\left( 1 \right) \right) }{ \left( 7+z \right)^{2} }\]

- baldymcgee6

|dw:1351751195729:dw|

- anonymous

@baldymcgee6 quick question. where did u get (-1) in the very first step in the equation

- baldymcgee6

|dw:1351751807412:dw|

- anonymous

yes

- baldymcgee6

|dw:1351751909040:dw|

- anonymous

also the second step the last part of the equation is cut off -2(7+z....

- baldymcgee6

sorry, my drawings keep getting cut off for some reason.
-2(7+z)^-3
Just using power rule there.

- anonymous

awesome, thanks a lot

- baldymcgee6

Welcome =D

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