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Calculate the derivative of the function.
Use Chain Rule
g(z) = (z^2/7+z)^2
 one year ago
 one year ago
Calculate the derivative of the function. Use Chain Rule g(z) = (z^2/7+z)^2
 one year ago
 one year ago

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baldymcgee6Best ResponseYou've already chosen the best response.1
Can you set it up?
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
im guessing its 2(z^2) x 2(7)
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351750568965:dwIs this the function?
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
@baldymcgee6 yes, and @sirm3d no the Z is squared
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
yea i just have a hard time with this one. maybe because its a different format
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
the first part is differentiating the square
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
\[2\left( \frac{ z^{2} }{ 7+z } \right)\]
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
There is an easier method if you want..
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351750799134:dwJust use the power rule and chain rule throughout, no need for quotient rule.
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
the second part is where the chain rule is used. Get the derivative of \[\frac{ z^{2} }{ 7+z }\] by the quotient rule for differentiation
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351750960037:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
You will actually need the product rule because the coefficient is a variable.
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
@sirm3d so the derivative would be 2x/7 ?and @baldymcgee6 so the previous equation you typed is the product rule? or chain?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
nope. the quotient rule on \[\frac{ z^{2} }{ 7+z }\] will produce \[\frac{ \left( 7+z \right)\left( 2z \right)\left( z^{2}\left( 1 \right) \right) }{ \left( 7+z \right)^{2} }\]
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351751195729:dw
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
@baldymcgee6 quick question. where did u get (1) in the very first step in the equation
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351751807412:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351751909040:dw
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
also the second step the last part of the equation is cut off 2(7+z....
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
sorry, my drawings keep getting cut off for some reason. 2(7+z)^3 Just using power rule there.
 one year ago

chrislb22Best ResponseYou've already chosen the best response.0
awesome, thanks a lot
 one year ago
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