chrislb22
Calculate the derivative of the function.
Use Chain Rule
g(z) = (z^2/7+z)^2



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baldymcgee6
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Can you set it up?

chrislb22
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im guessing its 2(z^2) x 2(7)

baldymcgee6
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dw:1351750568965:dwIs this the function?

chrislb22
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@baldymcgee6 yes, and @sirm3d no the Z is squared

sirm3d
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sorry i mistyped

chrislb22
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yea i just have a hard time with this one. maybe because its a different format

sirm3d
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the first part is differentiating the square

sirm3d
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\[2\left( \frac{ z^{2} }{ 7+z } \right)\]

baldymcgee6
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There is an easier method if you want..

baldymcgee6
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dw:1351750799134:dwJust use the power rule and chain rule throughout, no need for quotient rule.

sirm3d
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the second part is where the chain rule is used. Get the derivative of \[\frac{ z^{2} }{ 7+z }\] by the quotient rule for differentiation

baldymcgee6
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dw:1351750960037:dw

baldymcgee6
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You will actually need the product rule because the coefficient is a variable.

chrislb22
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@sirm3d so the derivative would be 2x/7 ?and @baldymcgee6 so the previous equation you typed is the product rule? or chain?

sirm3d
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nope. the quotient rule on \[\frac{ z^{2} }{ 7+z }\] will produce
\[\frac{ \left( 7+z \right)\left( 2z \right)\left( z^{2}\left( 1 \right) \right) }{ \left( 7+z \right)^{2} }\]

baldymcgee6
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dw:1351751195729:dw

chrislb22
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@baldymcgee6 quick question. where did u get (1) in the very first step in the equation

baldymcgee6
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dw:1351751807412:dw

chrislb22
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yes

baldymcgee6
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dw:1351751909040:dw

chrislb22
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also the second step the last part of the equation is cut off 2(7+z....

baldymcgee6
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sorry, my drawings keep getting cut off for some reason.
2(7+z)^3
Just using power rule there.

chrislb22
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awesome, thanks a lot

baldymcgee6
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Welcome =D