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aussy123

  • 2 years ago

How do you graph this x2- 3x + 2<= 0

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  1. aussy123
    • 2 years ago
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    \[x^2+3x+2\le0\]

  2. dopeboz
    • 2 years ago
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    wow!!!! i wouldnt know sorry

  3. aussy123
    • 2 years ago
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    its ok

  4. dopeboz
    • 2 years ago
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    k. but anyways i think your cute tho.

  5. helder_edwin
    • 2 years ago
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    first solve it as if it were an equation \[ \large x^2-3x+2=0 \]

  6. myko
    • 2 years ago
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    it's a parabola. To find where it crosses x-axis, write it like this: x^2-3x+2=(x-1)(x-2)=y so it will cross x-axis at x=1 and x=2 since you lookiing for points that are less than 0 it will be the part that is between this two points: |dw:1351781925843:dw|

  7. aussy123
    • 2 years ago
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    oh so I dont have to solve for anything

  8. myko
    • 2 years ago
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    |dw:1351782141285:dw|

  9. helder_edwin
    • 2 years ago
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    no it is not. @myko !!!!!

  10. helder_edwin
    • 2 years ago
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    the inequality has only ONE variable. its graph CANNOT bidimensional.

  11. helder_edwin
    • 2 years ago
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    anyways. myko just gave the answer \[ \large 0=x^2-3x+2=(x-1)(x-2) \] so x=1 or x=2

  12. myko
    • 2 years ago
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    look my last drawing x^2-3x+2=y is a function with range (vertex, infinity) it is less or equal 0 in the part that is under x-axis. That's what i drowed

  13. aussy123
    • 2 years ago
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    ok im a bit confused

  14. myko
    • 2 years ago
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    i gave the cross points to be able to grapfh it. The answer is the part under x.-axis

  15. myko
    • 2 years ago
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    @aussy123 don't be confused by @helder_edwin . The graph you looking for is: |dw:1351782419649:dw|

  16. aussy123
    • 2 years ago
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    Oh I see , @myko , I had to reread your first comment to get it, thanks because my book is giving me alot of confusing stuff

  17. myko
    • 2 years ago
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    yw

  18. helder_edwin
    • 2 years ago
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    again. the problem says: graph \(x^2-3x+2\leq0\) it does NOR say graph \(x^2-3x+2\leq y\).

  19. helder_edwin
    • 2 years ago
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    sorry *NOT

  20. myko
    • 2 years ago
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    problem says: \[y \leq 0\]

  21. myko
    • 2 years ago
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    you wrong pal

  22. myko
    • 2 years ago
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    How do you GRAPH this x2- 3x + 2<= 0

  23. helder_edwin
    • 2 years ago
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    it is a one-dimensional problem (one variable) but u turned it into a two-dimensional problem by adding a "y" that was never there.

  24. myko
    • 2 years ago
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    x2- 3x + 2 represents values of y, dude.

  25. myko
    • 2 years ago
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    it is one dimentional, :)

  26. myko
    • 2 years ago
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    y is DEPENDENT

  27. myko
    • 2 years ago
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    @helder_edwin

  28. helder_edwin
    • 2 years ago
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    but it was never there. u r not graphing a function "dude".

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