How do you graph this
x2- 3x + 2<= 0

- anonymous

How do you graph this
x2- 3x + 2<= 0

- chestercat

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- anonymous

\[x^2+3x+2\le0\]

- anonymous

wow!!!! i wouldnt know sorry

- anonymous

its ok

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## More answers

- anonymous

k. but anyways i think your cute tho.

- helder_edwin

first solve it as if it were an equation
\[ \large x^2-3x+2=0 \]

- anonymous

it's a parabola.
To find where it crosses x-axis, write it like this:
x^2-3x+2=(x-1)(x-2)=y
so it will cross x-axis at x=1 and x=2
since you lookiing for points that are less than 0 it will be the part that is between this two points:
|dw:1351781925843:dw|

- anonymous

oh so I dont have to solve for anything

- anonymous

|dw:1351782141285:dw|

- helder_edwin

no it is not. @myko !!!!!

- helder_edwin

the inequality has only ONE variable. its graph CANNOT bidimensional.

- helder_edwin

anyways. myko just gave the answer
\[ \large 0=x^2-3x+2=(x-1)(x-2) \]
so x=1 or x=2

- anonymous

look my last drawing
x^2-3x+2=y
is a function with range (vertex, infinity)
it is less or equal 0 in the part that is under x-axis. That's what i drowed

- anonymous

ok im a bit confused

- anonymous

i gave the cross points to be able to grapfh it. The answer is the part under x.-axis

- anonymous

@aussy123 don't be confused by @helder_edwin . The graph you looking for is:
|dw:1351782419649:dw|

- anonymous

Oh I see , @myko , I had to reread your first comment to get it, thanks because my book is giving me alot of confusing stuff

- anonymous

yw

- helder_edwin

again. the problem says: graph \(x^2-3x+2\leq0\)
it does NOR say graph \(x^2-3x+2\leq y\).

- helder_edwin

sorry *NOT

- anonymous

problem says:
\[y \leq 0\]

- anonymous

you wrong pal

- anonymous

How do you GRAPH this
x2- 3x + 2<= 0

- helder_edwin

it is a one-dimensional problem (one variable) but u turned it into a two-dimensional problem by adding a "y" that was never there.

- anonymous

x2- 3x + 2 represents values of y, dude.

- anonymous

it is one dimentional, :)

- anonymous

y is DEPENDENT

- anonymous

@helder_edwin

- helder_edwin

but it was never there. u r not graphing a function "dude".

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