Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

How do you graph this x2- 3x + 2<= 0

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

\[x^2+3x+2\le0\]
wow!!!! i wouldnt know sorry
its ok

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

k. but anyways i think your cute tho.
first solve it as if it were an equation \[ \large x^2-3x+2=0 \]
it's a parabola. To find where it crosses x-axis, write it like this: x^2-3x+2=(x-1)(x-2)=y so it will cross x-axis at x=1 and x=2 since you lookiing for points that are less than 0 it will be the part that is between this two points: |dw:1351781925843:dw|
oh so I dont have to solve for anything
|dw:1351782141285:dw|
no it is not. @myko !!!!!
the inequality has only ONE variable. its graph CANNOT bidimensional.
anyways. myko just gave the answer \[ \large 0=x^2-3x+2=(x-1)(x-2) \] so x=1 or x=2
look my last drawing x^2-3x+2=y is a function with range (vertex, infinity) it is less or equal 0 in the part that is under x-axis. That's what i drowed
ok im a bit confused
i gave the cross points to be able to grapfh it. The answer is the part under x.-axis
@aussy123 don't be confused by @helder_edwin . The graph you looking for is: |dw:1351782419649:dw|
Oh I see , @myko , I had to reread your first comment to get it, thanks because my book is giving me alot of confusing stuff
yw
again. the problem says: graph \(x^2-3x+2\leq0\) it does NOR say graph \(x^2-3x+2\leq y\).
sorry *NOT
problem says: \[y \leq 0\]
you wrong pal
How do you GRAPH this x2- 3x + 2<= 0
it is a one-dimensional problem (one variable) but u turned it into a two-dimensional problem by adding a "y" that was never there.
x2- 3x + 2 represents values of y, dude.
it is one dimentional, :)
y is DEPENDENT
but it was never there. u r not graphing a function "dude".

Not the answer you are looking for?

Search for more explanations.

Ask your own question