anonymous
  • anonymous
How do you graph this x2- 3x + 2<= 0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[x^2+3x+2\le0\]
anonymous
  • anonymous
wow!!!! i wouldnt know sorry
anonymous
  • anonymous
its ok

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anonymous
  • anonymous
k. but anyways i think your cute tho.
helder_edwin
  • helder_edwin
first solve it as if it were an equation \[ \large x^2-3x+2=0 \]
anonymous
  • anonymous
it's a parabola. To find where it crosses x-axis, write it like this: x^2-3x+2=(x-1)(x-2)=y so it will cross x-axis at x=1 and x=2 since you lookiing for points that are less than 0 it will be the part that is between this two points: |dw:1351781925843:dw|
anonymous
  • anonymous
oh so I dont have to solve for anything
anonymous
  • anonymous
|dw:1351782141285:dw|
helder_edwin
  • helder_edwin
no it is not. @myko !!!!!
helder_edwin
  • helder_edwin
the inequality has only ONE variable. its graph CANNOT bidimensional.
helder_edwin
  • helder_edwin
anyways. myko just gave the answer \[ \large 0=x^2-3x+2=(x-1)(x-2) \] so x=1 or x=2
anonymous
  • anonymous
look my last drawing x^2-3x+2=y is a function with range (vertex, infinity) it is less or equal 0 in the part that is under x-axis. That's what i drowed
anonymous
  • anonymous
ok im a bit confused
anonymous
  • anonymous
i gave the cross points to be able to grapfh it. The answer is the part under x.-axis
anonymous
  • anonymous
@aussy123 don't be confused by @helder_edwin . The graph you looking for is: |dw:1351782419649:dw|
anonymous
  • anonymous
Oh I see , @myko , I had to reread your first comment to get it, thanks because my book is giving me alot of confusing stuff
anonymous
  • anonymous
yw
helder_edwin
  • helder_edwin
again. the problem says: graph \(x^2-3x+2\leq0\) it does NOR say graph \(x^2-3x+2\leq y\).
helder_edwin
  • helder_edwin
sorry *NOT
anonymous
  • anonymous
problem says: \[y \leq 0\]
anonymous
  • anonymous
you wrong pal
anonymous
  • anonymous
How do you GRAPH this x2- 3x + 2<= 0
helder_edwin
  • helder_edwin
it is a one-dimensional problem (one variable) but u turned it into a two-dimensional problem by adding a "y" that was never there.
anonymous
  • anonymous
x2- 3x + 2 represents values of y, dude.
anonymous
  • anonymous
it is one dimentional, :)
anonymous
  • anonymous
y is DEPENDENT
anonymous
  • anonymous
@helder_edwin
helder_edwin
  • helder_edwin
but it was never there. u r not graphing a function "dude".

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