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aussy123 Group Title

How do you graph this x2- 3x + 2<= 0

  • 2 years ago
  • 2 years ago

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  1. aussy123 Group Title
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    \[x^2+3x+2\le0\]

    • 2 years ago
  2. dopeboz Group Title
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    wow!!!! i wouldnt know sorry

    • 2 years ago
  3. aussy123 Group Title
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    its ok

    • 2 years ago
  4. dopeboz Group Title
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    k. but anyways i think your cute tho.

    • 2 years ago
  5. helder_edwin Group Title
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    first solve it as if it were an equation \[ \large x^2-3x+2=0 \]

    • 2 years ago
  6. myko Group Title
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    it's a parabola. To find where it crosses x-axis, write it like this: x^2-3x+2=(x-1)(x-2)=y so it will cross x-axis at x=1 and x=2 since you lookiing for points that are less than 0 it will be the part that is between this two points: |dw:1351781925843:dw|

    • 2 years ago
  7. aussy123 Group Title
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    oh so I dont have to solve for anything

    • 2 years ago
  8. myko Group Title
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    |dw:1351782141285:dw|

    • 2 years ago
  9. helder_edwin Group Title
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    no it is not. @myko !!!!!

    • 2 years ago
  10. helder_edwin Group Title
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    the inequality has only ONE variable. its graph CANNOT bidimensional.

    • 2 years ago
  11. helder_edwin Group Title
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    anyways. myko just gave the answer \[ \large 0=x^2-3x+2=(x-1)(x-2) \] so x=1 or x=2

    • 2 years ago
  12. myko Group Title
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    look my last drawing x^2-3x+2=y is a function with range (vertex, infinity) it is less or equal 0 in the part that is under x-axis. That's what i drowed

    • 2 years ago
  13. aussy123 Group Title
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    ok im a bit confused

    • 2 years ago
  14. myko Group Title
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    i gave the cross points to be able to grapfh it. The answer is the part under x.-axis

    • 2 years ago
  15. myko Group Title
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    @aussy123 don't be confused by @helder_edwin . The graph you looking for is: |dw:1351782419649:dw|

    • 2 years ago
  16. aussy123 Group Title
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    Oh I see , @myko , I had to reread your first comment to get it, thanks because my book is giving me alot of confusing stuff

    • 2 years ago
  17. myko Group Title
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    yw

    • 2 years ago
  18. helder_edwin Group Title
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    again. the problem says: graph \(x^2-3x+2\leq0\) it does NOR say graph \(x^2-3x+2\leq y\).

    • 2 years ago
  19. helder_edwin Group Title
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    sorry *NOT

    • 2 years ago
  20. myko Group Title
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    problem says: \[y \leq 0\]

    • 2 years ago
  21. myko Group Title
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    you wrong pal

    • 2 years ago
  22. myko Group Title
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    How do you GRAPH this x2- 3x + 2<= 0

    • 2 years ago
  23. helder_edwin Group Title
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    it is a one-dimensional problem (one variable) but u turned it into a two-dimensional problem by adding a "y" that was never there.

    • 2 years ago
  24. myko Group Title
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    x2- 3x + 2 represents values of y, dude.

    • 2 years ago
  25. myko Group Title
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    it is one dimentional, :)

    • 2 years ago
  26. myko Group Title
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    y is DEPENDENT

    • 2 years ago
  27. myko Group Title
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    @helder_edwin

    • 2 years ago
  28. helder_edwin Group Title
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    but it was never there. u r not graphing a function "dude".

    • 2 years ago
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