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umm do yo know this formula for shift in an object's position:
\[\Large s=t(1-\frac{1}{n})\]

yes but in another shape

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t = real fepth
nv > nr
u mean i got like that

and s is raise

yes, that's right too.

that will give red that will be the least raise right ?

yes, absolutely.

is this equation comes from
Raise= real depth - apparent depth ?

yes it does.

yes it is. Good work. :)

thanks

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