solve the equations! 1.5-53t=0.1 1.5-53t= -0.1

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solve the equations! 1.5-53t=0.1 1.5-53t= -0.1

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i hate decimals multiply by 10 and solve \[15-530t=1\] for \(t\)
\[530t=14\] \[t=\frac{530}{14}\]
sorry if this is off subject but are you home schooled because I think I had this problem before

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Yeah, my alg teacher said there is a question like this on the alg test for tomorrow, and I need help.
oh I knew it!
the actual full question is this: Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = |1.5 – 53t|. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. but I got it down to some equations. But im still super confused. Do you think you could help?
I honestly didnt understand this question when I had it, but I think you can copy and paste this on google and yahoo may have it
I found this, it may help The car drives 53 miles per hour = 0.014722 miles per second 1 hour = 3600 seconds 0.1 miles takes 0.1 / 0.014722 = 6.7926 second

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