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ExtremeAnon Group Title

Simplify, help please!!??

  • 2 years ago
  • 2 years ago

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  1. ExtremeAnon Group Title
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    \[\LARGE 3\sqrt{128}\]

    • 2 years ago
  2. lyzzy7 Group Title
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    Wait, do you mean 128 (divided) by 3? or the squareroot?

    • 2 years ago
  3. fernando12 Group Title
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    33.94112

    • 2 years ago
  4. hartnn Group Title
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    its cube root, right ? \(\huge \sqrt[3]{128}\)

    • 2 years ago
  5. ExtremeAnon Group Title
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    \[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]

    • 2 years ago
  6. ExtremeAnon Group Title
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    @hartnn No, it's just \[\LARGE 3\sqrt{128}\]

    • 2 years ago
  7. hartnn Group Title
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    ok, can u simplify \(\huge \sqrt{128}=?\)

    • 2 years ago
  8. fernando12 Group Title
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    c

    • 2 years ago
  9. ExtremeAnon Group Title
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    yes? i think?

    • 2 years ago
  10. ExtremeAnon Group Title
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    @hartnn

    • 2 years ago
  11. hartnn Group Title
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    write it as 128 = 64*2 and u know square root of 64 ?

    • 2 years ago
  12. ExtremeAnon Group Title
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    8, right?

    • 2 years ago
  13. hartnn Group Title
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    \(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?

    • 2 years ago
  14. ExtremeAnon Group Title
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    .... i don't know. do i multiply the 8 & 3 to make 24?

    • 2 years ago
  15. hartnn Group Title
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    yes!

    • 2 years ago
  16. ExtremeAnon Group Title
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    so it would be B?

    • 2 years ago
  17. hartnn Group Title
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    absolutely :)

    • 2 years ago
  18. ExtremeAnon Group Title
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    Thank you so much for explaining it :)

    • 2 years ago
  19. hartnn Group Title
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    welcome ^_^

    • 2 years ago
  20. fernando12 Group Title
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    is c

    • 2 years ago
  21. ExtremeAnon Group Title
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    @fernando12 How did you get C?

    • 2 years ago
  22. hartnn Group Title
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    no, it isn't c.....

    • 2 years ago
  23. fernando12 Group Title
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    in my book

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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