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ExtremeAnon

Simplify, help please!!??

  • one year ago
  • one year ago

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  1. ExtremeAnon
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    \[\LARGE 3\sqrt{128}\]

    • one year ago
  2. lyzzy7
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    Wait, do you mean 128 (divided) by 3? or the squareroot?

    • one year ago
  3. fernando12
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    33.94112

    • one year ago
  4. hartnn
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    its cube root, right ? \(\huge \sqrt[3]{128}\)

    • one year ago
  5. ExtremeAnon
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    \[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]

    • one year ago
  6. ExtremeAnon
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    @hartnn No, it's just \[\LARGE 3\sqrt{128}\]

    • one year ago
  7. hartnn
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    ok, can u simplify \(\huge \sqrt{128}=?\)

    • one year ago
  8. fernando12
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    c

    • one year ago
  9. ExtremeAnon
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    yes? i think?

    • one year ago
  10. ExtremeAnon
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    @hartnn

    • one year ago
  11. hartnn
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    write it as 128 = 64*2 and u know square root of 64 ?

    • one year ago
  12. ExtremeAnon
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    8, right?

    • one year ago
  13. hartnn
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    \(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?

    • one year ago
  14. ExtremeAnon
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    .... i don't know. do i multiply the 8 & 3 to make 24?

    • one year ago
  15. hartnn
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    yes!

    • one year ago
  16. ExtremeAnon
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    so it would be B?

    • one year ago
  17. hartnn
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    absolutely :)

    • one year ago
  18. ExtremeAnon
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    Thank you so much for explaining it :)

    • one year ago
  19. hartnn
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    welcome ^_^

    • one year ago
  20. fernando12
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    is c

    • one year ago
  21. ExtremeAnon
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    @fernando12 How did you get C?

    • one year ago
  22. hartnn
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    no, it isn't c.....

    • one year ago
  23. fernando12
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    in my book

    • one year ago
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