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Simplify, help please!!??

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\[\LARGE 3\sqrt{128}\]
Wait, do you mean 128 (divided) by 3? or the squareroot?

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Other answers:

its cube root, right ? \(\huge \sqrt[3]{128}\)
\[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]
@hartnn No, it's just \[\LARGE 3\sqrt{128}\]
ok, can u simplify \(\huge \sqrt{128}=?\)
yes? i think?
write it as 128 = 64*2 and u know square root of 64 ?
8, right?
\(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?
.... i don't know. do i multiply the 8 & 3 to make 24?
so it would be B?
absolutely :)
Thank you so much for explaining it :)
welcome ^_^
is c
@fernando12 How did you get C?
no, it isn't c.....
in my book

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