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ExtremeAnon

  • 2 years ago

Simplify, help please!!??

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  1. ExtremeAnon
    • 2 years ago
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    \[\LARGE 3\sqrt{128}\]

  2. lyzzy7
    • 2 years ago
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    Wait, do you mean 128 (divided) by 3? or the squareroot?

  3. fernando12
    • 2 years ago
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    33.94112

  4. hartnn
    • 2 years ago
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    its cube root, right ? \(\huge \sqrt[3]{128}\)

  5. ExtremeAnon
    • 2 years ago
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    \[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]

  6. ExtremeAnon
    • 2 years ago
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    @hartnn No, it's just \[\LARGE 3\sqrt{128}\]

  7. hartnn
    • 2 years ago
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    ok, can u simplify \(\huge \sqrt{128}=?\)

  8. fernando12
    • 2 years ago
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    c

  9. ExtremeAnon
    • 2 years ago
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    yes? i think?

  10. ExtremeAnon
    • 2 years ago
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    @hartnn

  11. hartnn
    • 2 years ago
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    write it as 128 = 64*2 and u know square root of 64 ?

  12. ExtremeAnon
    • 2 years ago
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    8, right?

  13. hartnn
    • 2 years ago
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    \(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?

  14. ExtremeAnon
    • 2 years ago
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    .... i don't know. do i multiply the 8 & 3 to make 24?

  15. hartnn
    • 2 years ago
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    yes!

  16. ExtremeAnon
    • 2 years ago
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    so it would be B?

  17. hartnn
    • 2 years ago
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    absolutely :)

  18. ExtremeAnon
    • 2 years ago
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    Thank you so much for explaining it :)

  19. hartnn
    • 2 years ago
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    welcome ^_^

  20. fernando12
    • 2 years ago
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    is c

  21. ExtremeAnon
    • 2 years ago
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    @fernando12 How did you get C?

  22. hartnn
    • 2 years ago
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    no, it isn't c.....

  23. fernando12
    • 2 years ago
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    in my book

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