anonymous
  • anonymous
Simplify, help please!!??
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\LARGE 3\sqrt{128}\]
anonymous
  • anonymous
Wait, do you mean 128 (divided) by 3? or the squareroot?
anonymous
  • anonymous
33.94112

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hartnn
  • hartnn
its cube root, right ? \(\huge \sqrt[3]{128}\)
anonymous
  • anonymous
\[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]
anonymous
  • anonymous
@hartnn No, it's just \[\LARGE 3\sqrt{128}\]
hartnn
  • hartnn
ok, can u simplify \(\huge \sqrt{128}=?\)
anonymous
  • anonymous
c
anonymous
  • anonymous
yes? i think?
anonymous
  • anonymous
@hartnn
hartnn
  • hartnn
write it as 128 = 64*2 and u know square root of 64 ?
anonymous
  • anonymous
8, right?
hartnn
  • hartnn
\(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?
anonymous
  • anonymous
.... i don't know. do i multiply the 8 & 3 to make 24?
hartnn
  • hartnn
yes!
anonymous
  • anonymous
so it would be B?
hartnn
  • hartnn
absolutely :)
anonymous
  • anonymous
Thank you so much for explaining it :)
hartnn
  • hartnn
welcome ^_^
anonymous
  • anonymous
is c
anonymous
  • anonymous
@fernando12 How did you get C?
hartnn
  • hartnn
no, it isn't c.....
anonymous
  • anonymous
in my book

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