ExtremeAnon
Simplify, help please!!??



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ExtremeAnon
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\[\LARGE 3\sqrt{128}\]

lyzzy7
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Wait, do you mean 128 (divided) by 3? or the squareroot?

fernando12
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33.94112

hartnn
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its cube root, right ? \(\huge \sqrt[3]{128}\)

ExtremeAnon
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\[\large A) 192\sqrt{2}\]
\[\large B) 24\sqrt{2}\]
\[\large C) 11\sqrt{2}\]
\[\large D) 8\sqrt{2}\]

ExtremeAnon
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@hartnn No, it's just \[\LARGE 3\sqrt{128}\]

hartnn
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ok, can u simplify \(\huge \sqrt{128}=?\)

fernando12
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c

ExtremeAnon
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yes? i think?

ExtremeAnon
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@hartnn

hartnn
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write it as 128 = 64*2
and u know square root of 64 ?

ExtremeAnon
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8, right?

hartnn
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\(\text{yes so its }8\sqrt {2}\)
and 3 was multiplied with it, so u get ?

ExtremeAnon
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.... i don't know. do i multiply the 8 & 3 to make 24?

hartnn
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yes!

ExtremeAnon
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so it would be B?

hartnn
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absolutely :)

ExtremeAnon
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Thank you so much for explaining it :)

hartnn
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welcome ^_^

fernando12
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is c

ExtremeAnon
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@fernando12 How did you get C?

hartnn
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no, it isn't c.....

fernando12
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in my book