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\[\LARGE 3\sqrt{128}\]

Wait, do you mean 128 (divided) by 3? or the squareroot?

33.94112

its cube root, right ? \(\huge \sqrt[3]{128}\)

\[\large A) 192\sqrt{2}\]
\[\large B) 24\sqrt{2}\]
\[\large C) 11\sqrt{2}\]
\[\large D) 8\sqrt{2}\]

ok, can u simplify \(\huge \sqrt{128}=?\)

yes? i think?

write it as 128 = 64*2
and u know square root of 64 ?

8, right?

\(\text{yes so its }8\sqrt {2}\)
and 3 was multiplied with it, so u get ?

.... i don't know. do i multiply the 8 & 3 to make 24?

yes!

so it would be B?

absolutely :)

Thank you so much for explaining it :)

welcome ^_^

is c

@fernando12 How did you get C?

no, it isn't c.....

in my book