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AvengerVirus Group Title

A converging lens has a focal length in air = 20 cm.When it is immersed in a liquid of refractive index less than the refractive index of the material of the lens the focal length of lens in liquid a =20cm b >20cm c <20cm d change the sign

  • 2 years ago
  • 2 years ago

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  1. AvengerVirus Group Title
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    @rajathsbhat

    • 2 years ago
  2. AvengerVirus Group Title
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    i knew it's b but i can't explain good could u tell me why it is b ?

    • 2 years ago
  3. rajathsbhat Group Title
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    sure. good job though.

    • 2 years ago
  4. rajathsbhat Group Title
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    you see, in situations like this, you must look at something called 'relative refractive index'. relative refractive index n=n(glass)/n(water). Now you know that this 'n' in this situation is less than n(glass). Coming to the second part of determining the focus, you know that lesser the 'n', greater is the focal length right? So, the arrangement we have now will give you the exact same result as would a lens of refractive index n=n(glass)/n(water) placed in air. You know what I mean? Since this refractive index is less than the original refractive index, the focus length will be greater.

    • 2 years ago
  5. AvengerVirus Group Title
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    thanks that really explains good

    • 2 years ago
  6. rajathsbhat Group Title
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    :)

    • 2 years ago
  7. AvengerVirus Group Title
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    do u know much in ray and light optics ?

    • 2 years ago
  8. rajathsbhat Group Title
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    i good at high school optics, yeah.

    • 2 years ago
  9. AvengerVirus Group Title
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    ok i have many problem but i give myself chance to solve alone so can i revise my questions with later ?

    • 2 years ago
  10. rajathsbhat Group Title
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    sure. Just mention me in your question & I'll be there :)

    • 2 years ago
  11. AvengerVirus Group Title
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    ok thanks again :)

    • 2 years ago
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