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AvengerVirus
 2 years ago
A converging lens has a focal length in air = 20 cm.When it is immersed in a liquid of refractive index less than the refractive index of the material of
the lens the focal length of lens in liquid
a =20cm
b >20cm
c <20cm
d change the sign
AvengerVirus
 2 years ago
A converging lens has a focal length in air = 20 cm.When it is immersed in a liquid of refractive index less than the refractive index of the material of the lens the focal length of lens in liquid a =20cm b >20cm c <20cm d change the sign

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AvengerVirus
 2 years ago
Best ResponseYou've already chosen the best response.1i knew it's b but i can't explain good could u tell me why it is b ?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.2sure. good job though.

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.2you see, in situations like this, you must look at something called 'relative refractive index'. relative refractive index n=n(glass)/n(water). Now you know that this 'n' in this situation is less than n(glass). Coming to the second part of determining the focus, you know that lesser the 'n', greater is the focal length right? So, the arrangement we have now will give you the exact same result as would a lens of refractive index n=n(glass)/n(water) placed in air. You know what I mean? Since this refractive index is less than the original refractive index, the focus length will be greater.

AvengerVirus
 2 years ago
Best ResponseYou've already chosen the best response.1thanks that really explains good

AvengerVirus
 2 years ago
Best ResponseYou've already chosen the best response.1do u know much in ray and light optics ?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.2i good at high school optics, yeah.

AvengerVirus
 2 years ago
Best ResponseYou've already chosen the best response.1ok i have many problem but i give myself chance to solve alone so can i revise my questions with later ?

rajathsbhat
 2 years ago
Best ResponseYou've already chosen the best response.2sure. Just mention me in your question & I'll be there :)

AvengerVirus
 2 years ago
Best ResponseYou've already chosen the best response.1ok thanks again :)
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