## frx Group Title Show that $x ^{2}+18\ln(x)+11>12x$ for x>1, I have no idea how to do the 18ln(x) messes things up for me... 2 years ago 2 years ago

1. satellite73

damn i got cut off!!!

2. satellite73

here is my guess start with $x ^{2}-12x+18\ln(x)+11$

3. satellite73

take the derivative, show that it is positive on $$x>1$$

4. satellite73

that will mean your function is increasing, and since it is greater than zero at 1 (i am assuming it is, i didn't check) that means it will always be greater than zero

5. frx

That should do it, thanks!

6. satellite73

actually at 1 it is zero but that doesn't change the solution

7. satellite73

yw