anonymous
  • anonymous
Show that \[x ^{2}+18\ln(x)+11>12x \] for x>1, I have no idea how to do the 18ln(x) messes things up for me...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
damn i got cut off!!!
anonymous
  • anonymous
here is my guess start with \[x ^{2}-12x+18\ln(x)+11\]
anonymous
  • anonymous
take the derivative, show that it is positive on \(x>1\)

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anonymous
  • anonymous
that will mean your function is increasing, and since it is greater than zero at 1 (i am assuming it is, i didn't check) that means it will always be greater than zero
anonymous
  • anonymous
That should do it, thanks!
anonymous
  • anonymous
actually at 1 it is zero but that doesn't change the solution
anonymous
  • anonymous
yw

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