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frx
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Show that \[x ^{2}+18\ln(x)+11>12x \] for x>1, I have no idea how to do the 18ln(x) messes things up for me...
 2 years ago
 2 years ago
frx Group Title
Show that \[x ^{2}+18\ln(x)+11>12x \] for x>1, I have no idea how to do the 18ln(x) messes things up for me...
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.2
damn i got cut off!!!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
here is my guess start with \[x ^{2}12x+18\ln(x)+11\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
take the derivative, show that it is positive on \(x>1\)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
that will mean your function is increasing, and since it is greater than zero at 1 (i am assuming it is, i didn't check) that means it will always be greater than zero
 2 years ago

frx Group TitleBest ResponseYou've already chosen the best response.0
That should do it, thanks!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
actually at 1 it is zero but that doesn't change the solution
 2 years ago
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