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Given line AB, explain how to construct a square with sides of length AB.

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I'm not good with constructions, but you could construct two perpendicular lines at the end points of line AB, then use your compass to make sure those two lines were the same length as AB, then connect them with the fourth side. But your explanation probably needs to be more step-by-step...
Nice Question, i liked it. Made me think a bit and recollect my maths knowledge. Have the compass length as AB. Draw a straight line XY with a straight edge of length much greater than AB. Now mark a point P on XY. With P as center cut an arc on line XY for Q. Now PQ = AB. With P as center cut two arcs on either side of line XY. With Q as center cut two arcs on either side of line XY, so that they make two points with the arcs drawn with P as center. Mark those points as R and S. Now join P, R, Q, S. Now we have a paralleogram PRQS. PR = RQ = QS = SP parallelogram with all sides equal is a rhombus. The Diagonals of the rhombus are perpendicular to each other Now Draw a line UV with points R ans S. Now mark the point at which RS cuts PQ as A. With A as center cut an arc on UV to get the point C. With A as center cut an arc on XY to get the point B. With B as center cut an arc on one side of XY. With C as center cut an arc which cuts the ac drawn with B as center to get the point D. Now ABCD is the required Square with side AB.
yeah i think it needs to be like exactaly step by step..

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thank youu!!!!!!!!!!!!!

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