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ihavemathquestions

  • 2 years ago

1. Solve the system by elimination.

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  1. ihavemathquestions
    • 2 years ago
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  2. ChmE
    • 2 years ago
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    You need to do 2 at a time. Start with eq 2 & 3 2x -y + 5x = -9 2x - 10y - 5z = 0 subtract 2 from 1 2x -y + 5x = -9 -2x + 10y + 5z = 0 ( i changed the signs so we can add instead) 9y + 10z = -9 Now we have to to 1 & 3 x + 5y - 4z = -10 Multiply everything by -2 2x - 10y - 5z = 0 -2x - 10y + 8z = 20 2x - 10y - 5z = 0 (add them) -20y + 3z = 20

  3. ihavemathquestions
    • 2 years ago
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    So which is the answer?? (5, –1, 0) (–5, 1, 0) (–5, –1, 0) (–5, –1, –2)

  4. ChmE
    • 2 years ago
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    still working. Do you want to learn or just want the answer ?

  5. ihavemathquestions
    • 2 years ago
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    answer would be great

  6. ChmE
    • 2 years ago
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    good luck then

  7. ihavemathquestions
    • 2 years ago
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    ok id love to learn

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