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(x,y) x=n y=3(n_last)
Shouldnt it be more like y = x3 or y = 3x for the first one?
yes, the first one represents powers of 3\[(x,3^x)\] the second one looks a little square to me.....
Is the second one y=x^5 maybe?
no, give me a list of perfect square from 1 to 9 ...
1^2 = 1 2^2 = 4 3^2 = 9 ...
Ok? You want me to continue that or no?
continue it for the integers from 1 to 9; so from 1^2 to 9^2
Oh ok, you already did the first three, so the next would be: 4^2=16 5^2=25 6^2=36 7^2=49 8^2=64 and 9^2=81
now, notice that our outputs given are 5^2=25 6^2=36 7^2=49 8^2=64 9^2=81 now, when x=1, we need x to be 5 when x=2, we need x to be 6 when x=3, we need x to be 7 we need the x parts to be shifted by +4 do you see it?
I think I get ya, but whats an equasion for that? I understand the problem now though=) thanks
well it would be nice if x^2 would get us where we need to me, but we discovered the x needs to be shifted by +4 in order to make a math sooo y = (x+4)^2
soo many typos, sooo little time lol
Haha ok, I get it now...makes alot more sense=) and yes..thanks for your melp eben wif tybos=)
just to clarify ;) it would be nice if x^2 would get us where we need to be, but we discovered that x needs to be shifted by +4 in order to make a match ... good luck
Thanks again amistre, I really do appreciate it=D