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CliffSedgeBest ResponseYou've already chosen the best response.1
The parent function is the squaring function, \(y=x^2\) Look at all the ways \(y= x^2+6x5\) is different from the parent function. Putting it in vertex form will also help.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
how do i do that ? :$
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Vertex form? Complete the square.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
\[\huge (x3)^2+4\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
\[\huge Range = {\epsilon \mathbb{R} y \neq 0}\]
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Not for the function you have above, no.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
y doesnot equal 4** sorry typo
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
y can equal 4 here, just not anything above it.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
my solution says it says y can equal any real number :S
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
yeah i thought it was that too,
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Not for a parabola it can't.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
The domain is any real number for x...
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
yeah that's what i thought, look at number 8 http://mail.wecdsb.on.ca/~janet_maitland/FOV10006CFBC/FOV10006E9C7/unit%20three%20practice%20answers.pdf?Plugin=Loft
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
maybe she made a mistake :S
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Yeah, you can see clearly from the graph that the range is y≤4.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
okay thanks :D i thought i might have been doing to wrong
 one year ago
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