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burhan101

  • 3 years ago

Describe the transformation for : y= -x²+6x-5

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  1. CliffSedge
    • 3 years ago
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    The parent function is the squaring function, \(y=x^2\) Look at all the ways \(y= -x^2+6x-5\) is different from the parent function. Putting it in vertex form will also help.

  2. burhan101
    • 3 years ago
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    how do i do that ? :$

  3. CliffSedge
    • 3 years ago
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    Vertex form? Complete the square.

  4. burhan101
    • 3 years ago
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    ohhh okay !

  5. burhan101
    • 3 years ago
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    \[\huge -(x-3)^2+4\]

  6. CliffSedge
    • 3 years ago
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    That looks right.

  7. burhan101
    • 3 years ago
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    \[\huge Range = {\epsilon \mathbb{R}| y \neq 0}\]

  8. CliffSedge
    • 3 years ago
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    Not for the function you have above, no.

  9. burhan101
    • 3 years ago
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    y doesnot equal 4** sorry typo

  10. CliffSedge
    • 3 years ago
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    y can equal 4 here, just not anything above it.

  11. burhan101
    • 3 years ago
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    my solution says it says y can equal any real number :S

  12. burhan101
    • 3 years ago
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    yeah i thought it was that too,

  13. CliffSedge
    • 3 years ago
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    Not for a parabola it can't.

  14. CliffSedge
    • 3 years ago
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    The domain is any real number for x...

  15. burhan101
    • 3 years ago
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    yeah that's what i thought, look at number 8 http://mail.wecdsb.on.ca/~janet_maitland/FOV1-0006CFBC/FOV1-0006E9C7/unit%20three%20practice%20answers.pdf?Plugin=Loft

  16. burhan101
    • 3 years ago
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    maybe she made a mistake :S

  17. CliffSedge
    • 3 years ago
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    Yeah, you can see clearly from the graph that the range is y≤4.

  18. burhan101
    • 3 years ago
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    okay thanks :D i thought i might have been doing to wrong

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