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anonymous
 4 years ago
Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck  not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!
anonymous
 4 years ago
Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck  not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can do it the usual way.... (x^n) ' = nx^(n1) n is 5/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, so that is the derivative....?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I thought it was 5/2(x)^(3/2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Where do I proceed from here?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0plug in x=4 to find the slope (m) of the tangent to the curve at that point.. use y= mx +b with the point they gave in order to find b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh Okay. I was trying to plug the derivative in for m, but I guess that isn't correct.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, you just want the value of the derivative at that particular point...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not the general expression for the slope at any value of x..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So Is this the derivative? 5/2(x)^(3/2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks for the help!
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