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Study23
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Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck  not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!
 2 years ago
 2 years ago
Study23 Group Title
Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck  not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!
 2 years ago
 2 years ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you can do it the usual way.... (x^n) ' = nx^(n1) n is 5/2
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Okay, so that is the derivative....?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I thought it was 5/2(x)^(3/2)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Where do I proceed from here?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
plug in x=4 to find the slope (m) of the tangent to the curve at that point.. use y= mx +b with the point they gave in order to find b
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Oh Okay. I was trying to plug the derivative in for m, but I guess that isn't correct.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yeah, you just want the value of the derivative at that particular point...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
not the general expression for the slope at any value of x..
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
So Is this the derivative? 5/2(x)^(3/2)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
ok thanks for the help!
 2 years ago
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