anonymous
  • anonymous
Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck - not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
you can do it the usual way.... (x^n) ' = nx^(n-1) n is 5/2
anonymous
  • anonymous
Okay, so that is the derivative....?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
I thought it was 5/2(x)^(3/2)
anonymous
  • anonymous
Where do I proceed from here?
anonymous
  • anonymous
plug in x=4 to find the slope (m) of the tangent to the curve at that point.. use y= mx +b with the point they gave in order to find b
anonymous
  • anonymous
Oh Okay. I was trying to plug the derivative in for m, but I guess that isn't correct.
anonymous
  • anonymous
yeah, you just want the value of the derivative at that particular point...
anonymous
  • anonymous
not the general expression for the slope at any value of x..
anonymous
  • anonymous
So Is this the derivative? 5/2(x)^(3/2)
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok thanks for the help!
anonymous
  • anonymous
sure:)

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