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Study23
Find an equation to the tangent line to the curve at the given point. (So, I have to find the derivative, but Im stuck - not sure if I am doing this correctly). Function is y=x^(5/2) Point is \(\ (4,32). Please show me step by step! I'm really confused!
you can do it the usual way.... (x^n) ' = nx^(n-1) n is 5/2
Okay, so that is the derivative....?
I thought it was 5/2(x)^(3/2)
Where do I proceed from here?
plug in x=4 to find the slope (m) of the tangent to the curve at that point.. use y= mx +b with the point they gave in order to find b
Oh Okay. I was trying to plug the derivative in for m, but I guess that isn't correct.
yeah, you just want the value of the derivative at that particular point...
not the general expression for the slope at any value of x..
So Is this the derivative? 5/2(x)^(3/2)
ok thanks for the help!