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toadytica305
Group Title
If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?
 2 years ago
 2 years ago
toadytica305 Group Title
If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?
 2 years ago
 2 years ago

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Sheng Group TitleBest ResponseYou've already chosen the best response.1
Ok, so we know that at neutralization the amount of acid = amount of base However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used. What would that do to your molarity? (Hint M= n/L)
 2 years ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
Wouldn't it make it smaller than its true value?
 2 years ago

Sheng Group TitleBest ResponseYou've already chosen the best response.1
so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct
 2 years ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
i know the answer.. i just don't understand the reasoning behind it..
 2 years ago

Sheng Group TitleBest ResponseYou've already chosen the best response.1
Molarity = moles/volume if you have more volume, your Molarity will decrease, basic fraction property
 2 years ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
got it! thanks!
 2 years ago
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