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toadytica305

If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?

  • one year ago
  • one year ago

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  1. Sheng
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    Ok, so we know that at neutralization the amount of acid = amount of base However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used. What would that do to your molarity? (Hint M= n/L)

    • one year ago
  2. toadytica305
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    Wouldn't it make it smaller than its true value?

    • one year ago
  3. Sheng
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    so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct

    • one year ago
  4. toadytica305
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    i know the answer.. i just don't understand the reasoning behind it..

    • one year ago
  5. Sheng
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    Molarity = moles/volume if you have more volume, your Molarity will decrease, basic fraction property

    • one year ago
  6. toadytica305
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    got it! thanks!

    • one year ago
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