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If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?
 one year ago
 one year ago
If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?
 one year ago
 one year ago

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ShengBest ResponseYou've already chosen the best response.1
Ok, so we know that at neutralization the amount of acid = amount of base However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used. What would that do to your molarity? (Hint M= n/L)
 one year ago

toadytica305Best ResponseYou've already chosen the best response.0
Wouldn't it make it smaller than its true value?
 one year ago

ShengBest ResponseYou've already chosen the best response.1
so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct
 one year ago

toadytica305Best ResponseYou've already chosen the best response.0
i know the answer.. i just don't understand the reasoning behind it..
 one year ago

ShengBest ResponseYou've already chosen the best response.1
Molarity = moles/volume if you have more volume, your Molarity will decrease, basic fraction property
 one year ago
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