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If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?

Chemistry
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Ok, so we know that at neutralization the amount of acid = amount of base However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used. What would that do to your molarity? (Hint M= n/L)
Wouldn't it make it smaller than its true value?
so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct

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Other answers:

i know the answer.. i just don't understand the reasoning behind it..
Molarity = moles/volume if you have more volume, your Molarity will decrease, basic fraction property
got it! thanks!

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