A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?
 2 years ago
If you overshoot the endpoint in titration of the KHP, how would the calculated value for the molarity of the NaOH solution be affected?

This Question is Closed

Sheng
 2 years ago
Best ResponseYou've already chosen the best response.1Ok, so we know that at neutralization the amount of acid = amount of base However, if you overshoot and end up using too much base, your volume would increase for amount of NaOH used. What would that do to your molarity? (Hint M= n/L)

toadytica305
 2 years ago
Best ResponseYou've already chosen the best response.0Wouldn't it make it smaller than its true value?

Sheng
 2 years ago
Best ResponseYou've already chosen the best response.1so because you have a higher volume of NaOH, the amount/higher volume would yield a lesser concentration, so yes you're correct

toadytica305
 2 years ago
Best ResponseYou've already chosen the best response.0i know the answer.. i just don't understand the reasoning behind it..

Sheng
 2 years ago
Best ResponseYou've already chosen the best response.1Molarity = moles/volume if you have more volume, your Molarity will decrease, basic fraction property
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.