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3psilon
 2 years ago
I am terrible with Logs plz help
3psilon
 2 years ago
I am terrible with Logs plz help

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3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(x) = \log_{3}(\sqrt(x) + 3 \ \]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Log base 3 square root x plus 3

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0How do you find the inverse of this/

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1start with the fact that \(\log_3(\sqrt{x})=\frac{1}{2}\log_3(x)\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1is it the log of the whole thing?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0No just log base 3 square root x

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1i mean is it \[f(x)=\log_3(\sqrt{x}+3)\] or \[f(x)=\log_3(\sqrt{x})+3\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1ok then start with \[f(x)=\frac{1}{2}\log_3(x)+3\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1we can do the usual trick of writing \[y=\frac{1}{2}\log_3(x)+3\]then \[x=\frac{1}{2}\log_3(y)+3\] and solve for \(y\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you need the steps?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Yes please . I always get confused when there's stuff like log base 3

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.11) subtract 3 2) multiply by 2 3) raise 3 to everything

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{1}{2}\log_3(y)+3\] \[x3=\frac{1}{2}\log_3(y)\] \[2x6=\log_3(y)\] \[3^{2x6}=y\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1last step because \[\log_b(y)=x\iff b^x=y\]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Ohhh!!! Thank you so much !
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