anonymous
  • anonymous
use transformations to solve ;
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\large y=-2f (\frac{ 1 }{ 2 } x) +3\]
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
can someone explain ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
What I think : \[g(x)=-2f(\frac{ 1 }{ 2 }x) +3\] If you evaluate for x=4, \[g(4)=-2f(2)+3\] by looking at the graph, you see that f(2) = 0 thus, \[g(4)=3\]
anonymous
  • anonymous
hmm okay
anonymous
  • anonymous
I'm not sure what they mean by "use transformations"
anonymous
  • anonymous
they mean like apply all the changes to the graph looking at the formula above like the (-) means it's reflect on the x axis, but i dont understand the rest
anonymous
  • anonymous
You'd have to draw a second graph of \[y_{g}=g(x)\], using the formula and the graph \[y_{f}=(\frac{ 1 }{ 2 }x)\]
anonymous
  • anonymous
\[y _{g}=-2y _{f}+3\] \[y _{f}\] is found by looking at the first graph, at a value on the x-axis that is x/2

Looking for something else?

Not the answer you are looking for? Search for more explanations.