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Callisto Group TitleBest ResponseYou've already chosen the best response.3
For a = constant
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
\[v=\int a dt=at+c\]c = initial velocity So, \[v=u+at\]
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
good job
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
if a constan, a =0 v = u + at v = u + 0 v = u
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
\[x_f = \int v(t) dt=\int (\int a dt) dt = \int(at+u)dt = \frac{1}{2}at^2 + ut +c\], c = initial position So, \[x_f = ut +\frac{1}{2}at^2 + x_i\]\[x_fx_i = ut +\frac{1}{2}at^2\]\[s = ut+\frac{1}{2}at^2\]s=displacement.
 one year ago

gerryliyana Group TitleBest ResponseYou've already chosen the best response.0
for a = 0; s = ut + 0.5 at^2 s = ut + 0 s = ut
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
From the third post, \[s=ut+\frac{1}{2}at^2\]\[at^2+2ut 2s = 0\]\[t^2 + \frac{2u}{a}t  \frac{2s}{a}=0\]\[(t+\frac{u}{a})^2  \frac{u^2}{a^2}\frac{2s}{a}=0\]\[(t+\frac{u}{a})^2 = \frac{u^22as}{a^2}\]\[t+\frac{u}{a} = \frac{\sqrt{u^22as}}{a}\]\[t = \frac{\sqrt{u^22as}u}{a} (1)\] Put (1) into v=u+at \[v =u+a(\frac{\sqrt{u^22as}u}{a})\]\[v = u +\sqrt{u^22as}u\]\[v^2 = u^2 +2as\]
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
\[x_f = \int v(t) dt = v_{ave}t+C\]c = initial position \[x_f = v_{ave}t +x_i\]\[x_f = \frac{1}{2}(u+v)t +x_i \]\[s = \frac{1}{2}(u+v)t\]displacement = s = \(x_f  x_i\)
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
Probably something wrong with the last post, which is s=(1/2) (u+v)t.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
that's correct ... it assumes constant acceleration. that;s all.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
Seriously?! I did it!?!
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
let me see how can i put it up logically.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
dw:1351833416633:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
now you just need to show that for constant accn V_av = (u+v)/2 ... wanna try it?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
Huh!? I thought it's some maths.. Oh..How to start??
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
try using MVT
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
MVT.... again.../_\
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
well, you can do this without MVT ,,, i was wondering if i could improve my skills with MVT. try expanding v(t) in the expression of average.
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
or, V_av = s/t
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
expanding v(t)?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
v(t) = u + at
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
or simply put ,,, average velocity = distance/time
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
\[v_f= v_i+\int_0^{t_f} a dt=v_i + at\] So, \[v_f=v_i + at\]
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.3
\[x_f = x_i+\int_0^{t_f} v(t) dt= x_i+\int_0^{t_f} (v_i+at) dt = x_i+v_it+\frac{1}{2}at^2\] So, \[x_f = x_i+v_it+\frac{1}{2}at^2\] That is \[x_f  x_i = v_it+\frac{1}{2}at^2\]\[s= ut+\frac{1}{2}at^2\]
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
dw:1351853269560:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
dw:1351853406639:dw
 one year ago
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