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ggabby

log (2)^12

  • one year ago
  • one year ago

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  1. ggabby
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    |dw:1351832924289:dw|

    • one year ago
  2. ggabby
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    ???

    • one year ago
  3. sirm3d
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    \[2+\log_{2} 3\]

    • one year ago
  4. micahwood50
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    Well, I don't know what your question is. Let n be log₂12. (n = log₂12) Convert it into exponent form: 2ⁿ = 12, if you want exponent form. If you want to calculate it, you can simplify log₂12 to ln12/ln2. Does this help?

    • one year ago
  5. micahwood50
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    To get 2 + log₂3: log₂12 = log₂(3·4). = log₂4 + log₂3 = 2 + log₂3

    • one year ago
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