Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Ok, a little help with this speed measurement...In a minute I'll put a graph up

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Ok this is the graph, how fast is the car going from A-B and how fast is the car going from B-C?
1 Attachment
do you know a formula for speed?
Speed =Distance / time?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

distance = rate x time
correct
and i cant see any specific value on the graph
Are you supposed to answer in variable terms?
I know, thats the problem Im having... and maybe variables?
the distance covered from B to C is what? ignore the time part, how much does the distance change?
Ummmm.....
|dw:1351868494750:dw|
Well If I was to put up markers, about 2/3 as much as A-B... I really am uninformed in this topic...
the orientation of the chart might be confusing |dw:1351868677072:dw|
how fast do you have to be going to not move?
Not very lol, 0mph?
:) so at least from B to C, the speed is zero
But in A-B your distance variable is going up right?
correct, you are changing your distance from A to B by constant rate, and if we were able to have some points of reference we would be able to determine the speed by finding the slope of the line from A to B
are the point values for A and B given in a different part of the problem set?
Uh no, that graph is the only information ive been given
Other than the problems I typed
then the only thing we can really deduce is that the speed from A to B is greater than zero :)
Alrighty then=) ">0" will have to do=)
Thanks for your help again amistre=) should be my last question for the day lol
youre welcome ;)

Not the answer you are looking for?

Search for more explanations.

Ask your own question