anonymous
  • anonymous
3a – 4 ≤ 5 ?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
3a≤9 a≤3
anonymous
  • anonymous
3a - 4 + 4 ≤ 5 + 4 3a ≤ 9 9/3 a = 3
anonymous
  • anonymous
It shouldn't be an equality... you do need to solve for "a" the way you showed, but the result should still be an inequality like the way the problem started.

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anonymous
  • anonymous
3a - 4 + 4 ≤ 5 + 4 3a ≤ 9 3a/3 ≤ 9/3 a ≤ 3

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