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I need some help with Geometry, Finding Total Area in Prisms.

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Si, si
What is the question?
Find the Total Area of the Prism:

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Find the area of each side and add together... that's surface area I'm having a brain fart haha What is it you want to find?
Thats gross.
I want to find total Area
T.A. = ph + 2B
Rho as in density, right?
Greek letter p
perimeter of the base times height of the prism + 2Base = Total Area
Well the 2B part is easy. 2(area of the triangles)
Area of Triangle : 1/2 times 9 "correct" ?
1/2 time base of the triangle times the height of the triangle. Because you are only given the base, you need to find the height.
And to find the height we use pythag theorem correct?
So your new base would be 1.5 and the hypo would still be 3, yep
So the height would be a^2?
c= 3, b=1.5, and yep a= a
so when you plug into pythag, you would get that
So A= √6.75 ?
I have to get to my orgo class in 10 minutes, can you take it from here?
So i find the area of the triangle and multiply it by 2 Then i add ?
add that to the (perimeter of the base x height), which would be (3+3+3)(6)
Area of Triangle = 1.5√6.75 correct?
  • phi
btw, people would write \[\sqrt{6.75} \] as \[ \frac{3 \sqrt{3}}{2}\]
Okay i got it. Thanks so much!! I just needed a refresh it's been awhile :)
So it would be 4.5√3 / 2 @phi ?
  • phi
generally you don't mix decimals and fractions i.e. 4.5/2 If you have a multiple choice you probably would see the answer as a pure fraction \[ \frac{4}{9}\sqrt{3} \]
  • phi
double that for the other triangle now you have 3 faces that all look the same size 3x6 3 faces each 18 = 54 plus the two triangles 8/9 sqrt(3)
Other triangle?
  • phi
you have two triangles (the ends) and 3 "side faces" right?
Yeah my bad, sorry

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