Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 3 years ago

Exercise 2.5 works, I think, but with some parameters it complains that there's a 'math domain error' import math def roots (a,b,c): x = (math.sqrt(b**2 - 4*a*c)-b)/2 y = (-b - math.sqrt(b**2 - 4*a*c)-b)/2 print "x=",x print "y=", y

  • This Question is Closed
  1. Screech
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You have to test the value of the discriminant before taking the square root. Alternatively, if you can to do the optional part and have it produce complex root. Takes a little bit of extra effort. The sqrt function is still limited to non-negative values. So take the sqrt of the absolute value and multiply by "1J"

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy