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    • 2 years ago

    Exercise 2.5 works, I think, but with some parameters it complains that there's a 'math domain error' import math def roots (a,b,c): x = (math.sqrt(b**2 - 4*a*c)-b)/2 y = (-b - math.sqrt(b**2 - 4*a*c)-b)/2 print "x=",x print "y=", y

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    1. Screech
      • 2 years ago
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      You have to test the value of the discriminant before taking the square root. Alternatively, if you can to do the optional part and have it produce complex root. Takes a little bit of extra effort. The sqrt function is still limited to non-negative values. So take the sqrt of the absolute value and multiply by "1J"

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    spraguer (Moderator)
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