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As an exercise, write a function slope(x1, y1, x2, y2) that returns
the slope of the line through the points (x1, y1) and (x2, y2). Then use
this function in a function called intercept(x1, y1, x2, y2) that
returns the yintercept of the line through the points (x1, y1) and
(x2, y2). I have done the first part but i keep getting confused when i reach the second part.
 one year ago
 one year ago
As an exercise, write a function slope(x1, y1, x2, y2) that returns the slope of the line through the points (x1, y1) and (x2, y2). Then use this function in a function called intercept(x1, y1, x2, y2) that returns the yintercept of the line through the points (x1, y1) and (x2, y2). I have done the first part but i keep getting confused when i reach the second part.
 one year ago
 one year ago

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03225186213Best ResponseYou've already chosen the best response.0
from the first part make equation now for y intercept put x==0 in equation u will gwt intercepts
 one year ago

FabienTouneBest ResponseYou've already chosen the best response.0
If you consider the generic equation of a line : y = ax + b when you get the slope, you actually get the 'a' of your equation. You also have an x and an y (you can take for exemple x1 and y1). All you need to do is to infer the value of b, which is precisely the yintercept asked.
 one year ago

myndlessBest ResponseYou've already chosen the best response.1
the equation of a line is \[y=mx+b\], where m is the slope of the line, and b is the offset from the origin along the y axis. The yintercept is the value of y where x = 0, so\[y = 0m + b\]\[y = b\] For any point that you know exists on the line, you can solve for b. \[y_1 = mx_1 + b\]\[b = y_1  mx_1\]So all intercept(x1,y1,x2,y2) has to do is return y1  slope(x1,y1,x2,y2) * x1
 one year ago
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