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Sonikay
Group Title
When 4 inches are added to each side of square, its area increases by 64 square inches. What is the area of the initial square?
 one year ago
 one year ago
Sonikay Group Title
When 4 inches are added to each side of square, its area increases by 64 square inches. What is the area of the initial square?
 one year ago
 one year ago

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AlexUL Group TitleBest ResponseYou've already chosen the best response.2
\[A=x ^{2}\] with x being the length of the initial sides \[A+64=(x+4)\]
 one year ago

amruta1997 Group TitleBest ResponseYou've already chosen the best response.0
the area of previous square was 36 sq. inches
 one year ago

AlexUL Group TitleBest ResponseYou've already chosen the best response.2
\[(x+4)^{2}\] sorry
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
(x + 4)^2 = x^2 + 64. This will be a quadratic in "x".
 one year ago

Sonikay Group TitleBest ResponseYou've already chosen the best response.0
how did you get 36 so i can do the rest by myself?
 one year ago

amruta1997 Group TitleBest ResponseYou've already chosen the best response.0
it can be done by trial and error also
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
(x + 4)^2 = x^2 + 64 will become x^2 + 8x + 16 = x^2 + 64. Just combine terms and simplify.
 one year ago

Sonikay Group TitleBest ResponseYou've already chosen the best response.0
ok one thing why do you square it
 one year ago

amruta1997 Group TitleBest ResponseYou've already chosen the best response.0
area of square is its side squared
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
You have to get the area. Both of the first square and the second.
 one year ago

amruta1997 Group TitleBest ResponseYou've already chosen the best response.0
and x is the side
 one year ago

Sonikay Group TitleBest ResponseYou've already chosen the best response.0
thanks guys
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.0
The second area is (x + 4)^2 and the first area is x^2
 one year ago

amruta1997 Group TitleBest ResponseYou've already chosen the best response.0
its our pleasure
 one year ago

AlexUL Group TitleBest ResponseYou've already chosen the best response.2
\[A _{1}=x _{1}^{2}\] \[A _{2}=x _{2}^{2}\] \[A _{2}=A _{1}+64\] \[x _{2}=x _{1}+4\] Does that help?
 one year ago

Sonikay Group TitleBest ResponseYou've already chosen the best response.0
lol i got it
 one year ago

Sonikay Group TitleBest ResponseYou've already chosen the best response.0
ok so i did x^2 + 8x + 16 = x^2 + 64. and i got 6 what did i do wrong
 one year ago

AlexUL Group TitleBest ResponseYou've already chosen the best response.2
you got \[x _{1}=6\] so what's the area? Never forget what was the initial question
 one year ago
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