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Sonikay
 3 years ago
When 4 inches are added to each side of square, its area increases by 64 square inches. What is the area of the initial square?
Sonikay
 3 years ago
When 4 inches are added to each side of square, its area increases by 64 square inches. What is the area of the initial square?

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AlexUL
 3 years ago
Best ResponseYou've already chosen the best response.2\[A=x ^{2}\] with x being the length of the initial sides \[A+64=(x+4)\]

amruta1997
 3 years ago
Best ResponseYou've already chosen the best response.0the area of previous square was 36 sq. inches

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.0(x + 4)^2 = x^2 + 64. This will be a quadratic in "x".

Sonikay
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get 36 so i can do the rest by myself?

amruta1997
 3 years ago
Best ResponseYou've already chosen the best response.0it can be done by trial and error also

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.0(x + 4)^2 = x^2 + 64 will become x^2 + 8x + 16 = x^2 + 64. Just combine terms and simplify.

Sonikay
 3 years ago
Best ResponseYou've already chosen the best response.0ok one thing why do you square it

amruta1997
 3 years ago
Best ResponseYou've already chosen the best response.0area of square is its side squared

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.0You have to get the area. Both of the first square and the second.

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.0The second area is (x + 4)^2 and the first area is x^2

AlexUL
 3 years ago
Best ResponseYou've already chosen the best response.2\[A _{1}=x _{1}^{2}\] \[A _{2}=x _{2}^{2}\] \[A _{2}=A _{1}+64\] \[x _{2}=x _{1}+4\] Does that help?

Sonikay
 3 years ago
Best ResponseYou've already chosen the best response.0ok so i did x^2 + 8x + 16 = x^2 + 64. and i got 6 what did i do wrong

AlexUL
 3 years ago
Best ResponseYou've already chosen the best response.2you got \[x _{1}=6\] so what's the area? Never forget what was the initial question
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