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Study23
 3 years ago
Hmm.. I'm having difficulties differentiating this function: \(\ \frac{x}{x+\frac{c}{x}} \). Help, please!
Study23
 3 years ago
Hmm.. I'm having difficulties differentiating this function: \(\ \frac{x}{x+\frac{c}{x}} \). Help, please!

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Mathmuse
 3 years ago
Best ResponseYou've already chosen the best response.2function of x. c and z are constants. Direct quotient rule

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0@Mathmuse The fraction is \(\ \Huge \frac{c}{x}.\)

Mathmuse
 3 years ago
Best ResponseYou've already chosen the best response.2my bad, could not see it properly. In that case, get a common denominator of x on the bottom.

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0Could you help me with that?

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0Could I substitute the fraction with \(\ \huge c^{x} ? \)

Mathmuse
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{x}{x + \frac{c}{x}}=\frac{x}{(\frac{x^2+c}{x})}=\frac{x}{1}\frac{x}{(x^2+c)}\]

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0So how I go use the quotient rule to differentiate this function?

Mathmuse
 3 years ago
Best ResponseYou've already chosen the best response.2right. Or, because i always mess up the quotient rule, convert it to product rule

Mathmuse
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{x}{x^2+c}=x*(x^2+c)^{1}\]

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[(\frac{ x^2 }{ x^2+c })'=\frac{ (x^2)'(x^2+c)(x^2+c)'x^2 }{ (x^2+c)^2 }\]

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2x(x^2+c)2x(x^2) }{ (x^2+c)^2 }=\frac{ 2xc }{ (x^2+c)^2 }\]

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0Where did \(\ \Huge x^2+c \) come from??

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0@Mathmuse didnot write x^2 as nominator

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[x+\frac{ c }{ x }=\frac{ x^2+c }{ x }\]

Study23
 3 years ago
Best ResponseYou've already chosen the best response.0So how does that become x^2+c?

Jonask
 3 years ago
Best ResponseYou've already chosen the best response.0\[x \div \frac{ x^2+c }{ x }=x \times \frac{ x }{ x^2+c }=\frac{ x^2 }{ x^2+c }\]
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