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Find the sum of the geometric series 6+18+54+... to 6 terms.

Mathematics
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how?
\[S_n=\frac{ a(r^n-1) }{ r-1 }\]
\[a=6,r=3,n=6\]

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Other answers:

  • DLS
S=a(r^n - 1) / (r - 1) =>6(3^6-1)/5
so what would u substitute? and where?
idk
  • DLS
why infinity?when it says 6 terms
y is a and n=6
  • DLS
a is the 1st term and n=the power which u wrote 6 urself
what do u mean by that? how did u find 6 fr n?
  • DLS
Find the sum of the geometric series 6+18+54+... to 6 terms. sum of the geometric series 6+18+54+... to 6 terms. geometric series 6+18+54+... to 6 terms. 6+18+54+... to 6 terms. 6 terms.
oh ok thx

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