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Find the sum of the geometric series 6+18+54+... to 6 terms.
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how?
Jonask
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\[S_n=\frac{ a(r^n-1) }{ r-1 }\]
Jonask
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\[a=6,r=3,n=6\]
DLS
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S=a(r^n - 1) / (r - 1)
=>6(3^6-1)/5
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so what would u substitute? and where?
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idk
DLS
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why infinity?when it says 6 terms
Anikate
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y is a and n=6
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a is the 1st term
and n=the power which u wrote 6 urself
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what do u mean by that? how did u find 6 fr n?
DLS
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Find the sum of the geometric series 6+18+54+... to 6 terms.
sum of the geometric series 6+18+54+... to 6 terms.
geometric series 6+18+54+... to 6 terms.
6+18+54+... to 6 terms.
6 terms.
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oh ok thx