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Anikate

  • 3 years ago

Find the sum of the geometric series 6+18+54+... to 6 terms.

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  1. Anikate
    • 3 years ago
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    how?

  2. Jonask
    • 3 years ago
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    \[S_n=\frac{ a(r^n-1) }{ r-1 }\]

  3. Jonask
    • 3 years ago
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    \[a=6,r=3,n=6\]

  4. DLS
    • 3 years ago
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    S=a(r^n - 1) / (r - 1) =>6(3^6-1)/5

  5. Anikate
    • 3 years ago
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    so what would u substitute? and where?

  6. Anikate
    • 3 years ago
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    idk

  7. DLS
    • 3 years ago
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    why infinity?when it says 6 terms

  8. Anikate
    • 3 years ago
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    y is a and n=6

  9. DLS
    • 3 years ago
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    a is the 1st term and n=the power which u wrote 6 urself

  10. Anikate
    • 3 years ago
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    what do u mean by that? how did u find 6 fr n?

  11. DLS
    • 3 years ago
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    Find the sum of the geometric series 6+18+54+... to 6 terms. sum of the geometric series 6+18+54+... to 6 terms. geometric series 6+18+54+... to 6 terms. 6+18+54+... to 6 terms. 6 terms.

  12. Anikate
    • 3 years ago
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    oh ok thx

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