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Study23
 2 years ago
Best ResponseYou've already chosen the best response.0\(\ \huge \text{My steps:} \) \(\ \Huge f(x)=\frac{x}{(x^2+1)}.\) So to differentiate, I used the quotient rule: \(\ \Huge f'(x)=\frac{(1)(x^2+1)(x)(2x)}{(x^2+1)^2}, \) \(\ \Huge = \frac{x^2+12x^2}{(x^2+1)^2}, \) \(\ \Huge = \frac{x^2+1}{(x^2+1)^2}, \) \(\ \Huge = \frac{\cancel{x^2+1}}{\cancel{(x^2+1)}^2}, \) \(\ \Huge = \frac{1}{x^2+1} . \) \(\ \Huge \text{Is my work correct?} \)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\ \Huge = \frac{x^2+1}{(x^2+1)^2}\) cannot be simplified further. you cannot cancel like that.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\huge \frac{a+b}{a+b}\ne1\)

Study23
 2 years ago
Best ResponseYou've already chosen the best response.0@hartnn So is that all I can simplify?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yes, your final answer will be\( \Huge \frac{1x^2}{(x^2+1)^2}\)
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