Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Study23 Group TitleBest ResponseYou've already chosen the best response.0
\(\ \huge \text{My steps:} \) \(\ \Huge f(x)=\frac{x}{(x^2+1)}.\) So to differentiate, I used the quotient rule: \(\ \Huge f'(x)=\frac{(1)(x^2+1)(x)(2x)}{(x^2+1)^2}, \) \(\ \Huge = \frac{x^2+12x^2}{(x^2+1)^2}, \) \(\ \Huge = \frac{x^2+1}{(x^2+1)^2}, \) \(\ \Huge = \frac{\cancel{x^2+1}}{\cancel{(x^2+1)}^2}, \) \(\ \Huge = \frac{1}{x^2+1} . \) \(\ \Huge \text{Is my work correct?} \)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\ \Huge = \frac{x^2+1}{(x^2+1)^2}\) cannot be simplified further. you cannot cancel like that.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\huge \frac{a+b}{a+b}\ne1\)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
@hartnn So is that all I can simplify?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, your final answer will be\( \Huge \frac{1x^2}{(x^2+1)^2}\)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Okay, Thanks @hartnn!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.