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klimenkov Group TitleBest ResponseYou've already chosen the best response.0
\(f(x)=x+\sqrt{1+x^2}\)
 one year ago

IBRAHIM05 Group TitleBest ResponseYou've already chosen the best response.0
showe that f(x)is an odd function dw:1351889660643:dw
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.0
What will \(f(x)\) be?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
if f(x)=f(x) then it is odd f(x)=f(x) even
 one year ago
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