At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

\[\frac{x^2}{(x-5)^2}\]Can you take derivatives?

I even put the function into a graphing calculator. i still cant get the right answer.

Can you type here what you've got?

Ok. I will type an answer for you.

all those answers are right. just need 7 and 8

Oh. Sorry. I must check it again!

Sorry, I'm not very good in English. Am I right?|dw:1351890529218:dw|

left is concave downward, right is concave up. so you have it backwards

|dw:1351890663750:dw|

I can solve it right here if you want. It will be not so long.

your right. no need to go any further. :P

ye, i was having a tough time with that. :l

Ok, ask anything you like.

http://gyazo.com/3d89eca12903c12ca28e608233e9f102
find critical points

Hate this congratulations :)

:o?

3, and -3

Yes, they are critical.

and 0

Are you sure that 0 is a critical point?

your right, its not. f'(0) does not equal 0

but it wont even accept -3 or 3

ugh. wait. i think f'(0)= 0. so it must be a critical point

No. It is not right. The derivative is:\[\frac{-4 ( x^2+9 )}{( x^2-9 )^2}\]

oh. so what do you do from there. set it equal to zero and solve? that would be -3 and 3 right?

In points -3 and 3 it doesn't exist, so both of them are critical.

ok so that is the answer?

Yes.
What is the definition of the critical point on your site?

http://gyazo.com/a531cae84cdcc8b853ca750f1e2b5e0c

im not entirely sure. '_'

Try to type -3,3 insted of 3,-3

http://gyazo.com/0354e3dc53f2b3172ff9cbbfd156f2a1

this is the problem im having. it wont accept anything.

Hm..did you type None into this field?

omg. that actually worked

None?

yes. Thanks a lot for the help =]