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anonymous
 4 years ago
Where is this function concave up and concave down.
x^2/(x5)^2
anonymous
 4 years ago
Where is this function concave up and concave down. x^2/(x5)^2

This Question is Closed

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{x^2}{(x5)^2}\]Can you take derivatives?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. I know i have to take the second derivative, but i having trouble finding out where the 2nd derivative equals zero.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I even put the function into a graphing calculator. i still cant get the right answer.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Can you type here what you've got?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0going to take me a while to get it, have to do chain rule and everything. '_' you can just post the answer if you want. >.> already been on this problem for like an hour

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Ok. I will type an answer for you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this was a multiple part question, this is what i have so far. http://gyazo.com/003eb77ccf9977811aa71cf7f65fb35f

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all those answers are right. just need 7 and 8

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1\(f''(x)=\frac2{(5 + x)^2}  \frac{8 x}{(5 + x)^3} + \frac{6 x^2}{(5 + x)^4}\) The horizontal asymtote isn't right.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Oh. Sorry. I must check it again!

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry, I'm not very good in English. Am I right?dw:1351890529218:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0left is concave downward, right is concave up. so you have it backwards

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351890663750:dw

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Ok. So when \(x\in(\infty,\frac52)\) it is concave downward. \(x\in(\frac52,5)\bigcup(5,+\infty)\) it is concave upward.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1I can solve it right here if you want. It will be not so long.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your right. no need to go any further. :P

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1All you have to do is to solve this:\[\frac2{(5 + x)^2}  \frac{8 x}{(5 + x)^3} + \frac{6 x^2}{(5 + x)^4}=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ye, i was having a tough time with that. :l

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm. while your here. could you answer 1 small part to another question? pretty straight forward this time

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Ok, ask anything you like.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://gyazo.com/3d89eca12903c12ca28e608233e9f102 find critical points

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Hate this congratulations :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0people told me there are not critical points to that function, but im not entirely sure if their correct.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1The definition of the critical point says that it is that point where the derivative of the function is equal to zero or DOES NOT EXIST. It is your case. Wat are the point where it doesn't exist?

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, they are critical.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but my site says 3, 3 and 0 are not critical points http://gyazo.com/77d0af7eb8d1e3ce273ff32c24eb58ca

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Are you sure that 0 is a critical point?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your right, its not. f'(0) does not equal 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but it wont even accept 3 or 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ugh. wait. i think f'(0)= 0. so it must be a critical point

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1No. It is not right. The derivative is:\[\frac{4 ( x^2+9 )}{( x^29 )^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh. so what do you do from there. set it equal to zero and solve? that would be 3 and 3 right?

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1In points 3 and 3 it doesn't exist, so both of them are critical.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so that is the answer?

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Yes. What is the definition of the critical point on your site?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not entirely sure. '_'

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Try to type 3,3 insted of 3,3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the problem im having. it wont accept anything.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1Hm..did you type None into this field?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0omg. that actually worked

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. Thanks a lot for the help =]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did a combined total of 180 tries on both of the question i asked you. finally got the right answers.

klimenkov
 4 years ago
Best ResponseYou've already chosen the best response.1It is strange. Ask your teacher the definition of the critical point. Hope you will solve different problems easily in the future. Good luck for you. I wish you a lot of well. Hope you understand.
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