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klimenkovBest ResponseYou've already chosen the best response.1
\[\frac{x^2}{(x5)^2}\]Can you take derivatives?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
yes. I know i have to take the second derivative, but i having trouble finding out where the 2nd derivative equals zero.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
I even put the function into a graphing calculator. i still cant get the right answer.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Can you type here what you've got?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
going to take me a while to get it, have to do chain rule and everything. '_' you can just post the answer if you want. >.> already been on this problem for like an hour
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Ok. I will type an answer for you.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
this was a multiple part question, this is what i have so far. http://gyazo.com/003eb77ccf9977811aa71cf7f65fb35f
 one year ago

steel11Best ResponseYou've already chosen the best response.0
all those answers are right. just need 7 and 8
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
\(f''(x)=\frac2{(5 + x)^2}  \frac{8 x}{(5 + x)^3} + \frac{6 x^2}{(5 + x)^4}\) The horizontal asymtote isn't right.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Oh. Sorry. I must check it again!
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Sorry, I'm not very good in English. Am I right?dw:1351890529218:dw
 one year ago

steel11Best ResponseYou've already chosen the best response.0
left is concave downward, right is concave up. so you have it backwards
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Ok. So when \(x\in(\infty,\frac52)\) it is concave downward. \(x\in(\frac52,5)\bigcup(5,+\infty)\) it is concave upward.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
I can solve it right here if you want. It will be not so long.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
your right. no need to go any further. :P
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
All you have to do is to solve this:\[\frac2{(5 + x)^2}  \frac{8 x}{(5 + x)^3} + \frac{6 x^2}{(5 + x)^4}=0\]
 one year ago

steel11Best ResponseYou've already chosen the best response.0
ye, i was having a tough time with that. :l
 one year ago

steel11Best ResponseYou've already chosen the best response.0
hmm. while your here. could you answer 1 small part to another question? pretty straight forward this time
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Ok, ask anything you like.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
http://gyazo.com/3d89eca12903c12ca28e608233e9f102 find critical points
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Hate this congratulations :)
 one year ago

steel11Best ResponseYou've already chosen the best response.0
people told me there are not critical points to that function, but im not entirely sure if their correct.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
The definition of the critical point says that it is that point where the derivative of the function is equal to zero or DOES NOT EXIST. It is your case. Wat are the point where it doesn't exist?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Yes, they are critical.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
but my site says 3, 3 and 0 are not critical points http://gyazo.com/77d0af7eb8d1e3ce273ff32c24eb58ca
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Are you sure that 0 is a critical point?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
your right, its not. f'(0) does not equal 0
 one year ago

steel11Best ResponseYou've already chosen the best response.0
but it wont even accept 3 or 3
 one year ago

steel11Best ResponseYou've already chosen the best response.0
ugh. wait. i think f'(0)= 0. so it must be a critical point
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
No. It is not right. The derivative is:\[\frac{4 ( x^2+9 )}{( x^29 )^2}\]
 one year ago

steel11Best ResponseYou've already chosen the best response.0
oh. so what do you do from there. set it equal to zero and solve? that would be 3 and 3 right?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
In points 3 and 3 it doesn't exist, so both of them are critical.
 one year ago

steel11Best ResponseYou've already chosen the best response.0
ok so that is the answer?
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Yes. What is the definition of the critical point on your site?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
http://gyazo.com/a531cae84cdcc8b853ca750f1e2b5e0c
 one year ago

steel11Best ResponseYou've already chosen the best response.0
im not entirely sure. '_'
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Try to type 3,3 insted of 3,3
 one year ago

steel11Best ResponseYou've already chosen the best response.0
http://gyazo.com/0354e3dc53f2b3172ff9cbbfd156f2a1
 one year ago

steel11Best ResponseYou've already chosen the best response.0
this is the problem im having. it wont accept anything.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
Hm..did you type None into this field?
 one year ago

steel11Best ResponseYou've already chosen the best response.0
omg. that actually worked
 one year ago

steel11Best ResponseYou've already chosen the best response.0
yes. Thanks a lot for the help =]
 one year ago

steel11Best ResponseYou've already chosen the best response.0
i did a combined total of 180 tries on both of the question i asked you. finally got the right answers.
 one year ago

klimenkovBest ResponseYou've already chosen the best response.1
It is strange. Ask your teacher the definition of the critical point. Hope you will solve different problems easily in the future. Good luck for you. I wish you a lot of well. Hope you understand.
 one year ago
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