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\[\frac{x^2}{(x-5)^2}\]Can you take derivatives?

I even put the function into a graphing calculator. i still cant get the right answer.

Can you type here what you've got?

Ok. I will type an answer for you.

all those answers are right. just need 7 and 8

Oh. Sorry. I must check it again!

Sorry, I'm not very good in English. Am I right?|dw:1351890529218:dw|

left is concave downward, right is concave up. so you have it backwards

|dw:1351890663750:dw|

I can solve it right here if you want. It will be not so long.

your right. no need to go any further. :P

ye, i was having a tough time with that. :l

Ok, ask anything you like.

http://gyazo.com/3d89eca12903c12ca28e608233e9f102
find critical points

Hate this congratulations :)

:o?

3, and -3

Yes, they are critical.

and 0

Are you sure that 0 is a critical point?

your right, its not. f'(0) does not equal 0

but it wont even accept -3 or 3

ugh. wait. i think f'(0)= 0. so it must be a critical point

No. It is not right. The derivative is:\[\frac{-4 ( x^2+9 )}{( x^2-9 )^2}\]

oh. so what do you do from there. set it equal to zero and solve? that would be -3 and 3 right?

In points -3 and 3 it doesn't exist, so both of them are critical.

ok so that is the answer?

Yes.
What is the definition of the critical point on your site?

http://gyazo.com/a531cae84cdcc8b853ca750f1e2b5e0c

im not entirely sure. '_'

Try to type -3,3 insted of 3,-3

http://gyazo.com/0354e3dc53f2b3172ff9cbbfd156f2a1

this is the problem im having. it wont accept anything.

Hm..did you type None into this field?

omg. that actually worked

None?

yes. Thanks a lot for the help =]