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awesomeness123

Lol this is FOR REAL my last question of today :) sorry guys! Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = -3/2x y = 3/2x - 6 y = -2/3x -5/3 y = 2/3x - 13/3

  • one year ago
  • one year ago

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  1. awesomeness123
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    @AriPotta im sorry lol

    • one year ago
  2. awesomeness123
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    @Hero promise this is my last today

    • one year ago
  3. awesomeness123
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    im still confused bout this

    • one year ago
  4. awesomeness123
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    |dw:1351893998329:dw|

    • one year ago
  5. awesomeness123
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    so first -5,0 and 0,3 i plug into the y2-y1 thing

    • one year ago
  6. awesomeness123
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    then i got 3/5

    • one year ago
  7. awesomeness123
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    since its perp i change it to -5/3

    • one year ago
  8. awesomeness123
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    then i do the y-y1 formula with the point 2,-3

    • one year ago
  9. awesomeness123
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    (btw I need u to check it

    • one year ago
  10. awesomeness123
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    then im confused help!

    • one year ago
  11. JakeV8
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    is (2,-3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as -5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y - y1 = m(x -x1) where (x1, y1) is your point, and m is your slope.

    • one year ago
  12. awesomeness123
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    please hurry as i need to go soon

    • one year ago
  13. awesomeness123
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    yes

    • one year ago
  14. awesomeness123
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    see i did that but i didnt get any of the options

    • one year ago
  15. JakeV8
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    so it's y - (-3) = (-5/3)(x-2) y + 3 = -5/3x -10/3 y = -5/3 x -19/3

    • one year ago
  16. awesomeness123
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    but is that an option?

    • one year ago
  17. JakeV8
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    oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.

    • one year ago
  18. awesomeness123
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    hold on ill attach a file!

    • one year ago
  19. awesomeness123
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    • one year ago
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  20. JakeV8
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    The problem is your slope. The actual line looks like it goes through (-5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is -3/2 And your equation becomes: y - (-3) = -3/2 (x - 2) y + 3 = -3/2 x + 3 y = -3/2 x

    • one year ago
  21. awesomeness123
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    thank you!!! SO MUCH!! muah thxx

    • one year ago
  22. JakeV8
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    you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.

    • one year ago
  23. awesomeness123
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    got it!

    • one year ago
  24. JakeV8
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    glad to help :)

    • one year ago
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