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awesomeness123

  • 2 years ago

Lol this is FOR REAL my last question of today :) sorry guys! Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = -3/2x y = 3/2x - 6 y = -2/3x -5/3 y = 2/3x - 13/3

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  1. awesomeness123
    • 2 years ago
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    @AriPotta im sorry lol

  2. awesomeness123
    • 2 years ago
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    @Hero promise this is my last today

  3. awesomeness123
    • 2 years ago
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    im still confused bout this

  4. awesomeness123
    • 2 years ago
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    |dw:1351893998329:dw|

  5. awesomeness123
    • 2 years ago
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    so first -5,0 and 0,3 i plug into the y2-y1 thing

  6. awesomeness123
    • 2 years ago
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    then i got 3/5

  7. awesomeness123
    • 2 years ago
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    since its perp i change it to -5/3

  8. awesomeness123
    • 2 years ago
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    then i do the y-y1 formula with the point 2,-3

  9. awesomeness123
    • 2 years ago
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    (btw I need u to check it

  10. awesomeness123
    • 2 years ago
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    then im confused help!

  11. JakeV8
    • 2 years ago
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    is (2,-3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as -5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y - y1 = m(x -x1) where (x1, y1) is your point, and m is your slope.

  12. awesomeness123
    • 2 years ago
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    please hurry as i need to go soon

  13. awesomeness123
    • 2 years ago
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    yes

  14. awesomeness123
    • 2 years ago
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    see i did that but i didnt get any of the options

  15. JakeV8
    • 2 years ago
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    so it's y - (-3) = (-5/3)(x-2) y + 3 = -5/3x -10/3 y = -5/3 x -19/3

  16. awesomeness123
    • 2 years ago
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    but is that an option?

  17. JakeV8
    • 2 years ago
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    oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.

  18. awesomeness123
    • 2 years ago
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    hold on ill attach a file!

  19. awesomeness123
    • 2 years ago
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    1 Attachment
  20. JakeV8
    • 2 years ago
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    The problem is your slope. The actual line looks like it goes through (-5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is -3/2 And your equation becomes: y - (-3) = -3/2 (x - 2) y + 3 = -3/2 x + 3 y = -3/2 x

  21. awesomeness123
    • 2 years ago
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    thank you!!! SO MUCH!! muah thxx

  22. JakeV8
    • 2 years ago
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    you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.

  23. awesomeness123
    • 2 years ago
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    got it!

  24. JakeV8
    • 2 years ago
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    glad to help :)

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