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awesomeness123
Group Title
Lol this is FOR REAL my last question of today :) sorry guys!
Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown.
y = 3/2x
y = 3/2x  6
y = 2/3x 5/3
y = 2/3x  13/3
 one year ago
 one year ago
awesomeness123 Group Title
Lol this is FOR REAL my last question of today :) sorry guys! Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = 3/2x y = 3/2x  6 y = 2/3x 5/3 y = 2/3x  13/3
 one year ago
 one year ago

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awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
@AriPotta im sorry lol
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
@Hero promise this is my last today
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
im still confused bout this
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351893998329:dw
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
so first 5,0 and 0,3 i plug into the y2y1 thing
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then i got 3/5
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
since its perp i change it to 5/3
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then i do the yy1 formula with the point 2,3
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
(btw I need u to check it
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then im confused help!
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
is (2,3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as 5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y  y1 = m(x x1) where (x1, y1) is your point, and m is your slope.
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
please hurry as i need to go soon
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
yes
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
see i did that but i didnt get any of the options
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
so it's y  (3) = (5/3)(x2) y + 3 = 5/3x 10/3 y = 5/3 x 19/3
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
but is that an option?
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
hold on ill attach a file!
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
The problem is your slope. The actual line looks like it goes through (5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is 3/2 And your equation becomes: y  (3) = 3/2 (x  2) y + 3 = 3/2 x + 3 y = 3/2 x
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
thank you!!! SO MUCH!! muah thxx
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.
 one year ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
got it!
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
glad to help :)
 one year ago
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