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awesomeness123
 3 years ago
Lol this is FOR REAL my last question of today :) sorry guys!
Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown.
y = 3/2x
y = 3/2x  6
y = 2/3x 5/3
y = 2/3x  13/3
awesomeness123
 3 years ago
Lol this is FOR REAL my last question of today :) sorry guys! Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = 3/2x y = 3/2x  6 y = 2/3x 5/3 y = 2/3x  13/3

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awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0@AriPotta im sorry lol

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0@Hero promise this is my last today

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0im still confused bout this

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351893998329:dw

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0so first 5,0 and 0,3 i plug into the y2y1 thing

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0since its perp i change it to 5/3

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0then i do the yy1 formula with the point 2,3

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0(btw I need u to check it

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0then im confused help!

JakeV8
 3 years ago
Best ResponseYou've already chosen the best response.1is (2,3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as 5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y  y1 = m(x x1) where (x1, y1) is your point, and m is your slope.

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0please hurry as i need to go soon

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0see i did that but i didnt get any of the options

JakeV8
 3 years ago
Best ResponseYou've already chosen the best response.1so it's y  (3) = (5/3)(x2) y + 3 = 5/3x 10/3 y = 5/3 x 19/3

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0but is that an option?

JakeV8
 3 years ago
Best ResponseYou've already chosen the best response.1oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0hold on ill attach a file!

JakeV8
 3 years ago
Best ResponseYou've already chosen the best response.1The problem is your slope. The actual line looks like it goes through (5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is 3/2 And your equation becomes: y  (3) = 3/2 (x  2) y + 3 = 3/2 x + 3 y = 3/2 x

awesomeness123
 3 years ago
Best ResponseYou've already chosen the best response.0thank you!!! SO MUCH!! muah thxx

JakeV8
 3 years ago
Best ResponseYou've already chosen the best response.1you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.
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