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awesomeness123
Group Title
Lol this is FOR REAL my last question of today :) sorry guys!
Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown.
y = 3/2x
y = 3/2x  6
y = 2/3x 5/3
y = 2/3x  13/3
 2 years ago
 2 years ago
awesomeness123 Group Title
Lol this is FOR REAL my last question of today :) sorry guys! Choose the slopeintercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = 3/2x y = 3/2x  6 y = 2/3x 5/3 y = 2/3x  13/3
 2 years ago
 2 years ago

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awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
@AriPotta im sorry lol
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
@Hero promise this is my last today
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
im still confused bout this
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351893998329:dw
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
so first 5,0 and 0,3 i plug into the y2y1 thing
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then i got 3/5
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
since its perp i change it to 5/3
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then i do the yy1 formula with the point 2,3
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
(btw I need u to check it
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
then im confused help!
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
is (2,3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as 5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y  y1 = m(x x1) where (x1, y1) is your point, and m is your slope.
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
please hurry as i need to go soon
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
see i did that but i didnt get any of the options
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
so it's y  (3) = (5/3)(x2) y + 3 = 5/3x 10/3 y = 5/3 x 19/3
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
but is that an option?
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
hold on ill attach a file!
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
The problem is your slope. The actual line looks like it goes through (5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is 3/2 And your equation becomes: y  (3) = 3/2 (x  2) y + 3 = 3/2 x + 3 y = 3/2 x
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
thank you!!! SO MUCH!! muah thxx
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.
 2 years ago

awesomeness123 Group TitleBest ResponseYou've already chosen the best response.0
got it!
 2 years ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.1
glad to help :)
 2 years ago
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