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@AriPotta im sorry lol
@Hero promise this is my last today
im still confused bout this
so first -5,0 and 0,3 i plug into the y2-y1 thing
then i got 3/5
since its perp i change it to -5/3
then i do the y-y1 formula with the point 2,-3
(btw I need u to check it
then im confused help!
is (2,-3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as -5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y - y1 = m(x -x1) where (x1, y1) is your point, and m is your slope.
please hurry as i need to go soon
see i did that but i didnt get any of the options
so it's y - (-3) = (-5/3)(x-2) y + 3 = -5/3x -10/3 y = -5/3 x -19/3
but is that an option?
oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.
hold on ill attach a file!
The problem is your slope. The actual line looks like it goes through (-5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is -3/2 And your equation becomes: y - (-3) = -3/2 (x - 2) y + 3 = -3/2 x + 3 y = -3/2 x
thank you!!! SO MUCH!! muah thxx
you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.
glad to help :)