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awesomeness123 Group Title

Lol this is FOR REAL my last question of today :) sorry guys! Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = -3/2x y = 3/2x - 6 y = -2/3x -5/3 y = 2/3x - 13/3

  • 2 years ago
  • 2 years ago

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  1. awesomeness123 Group Title
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    @AriPotta im sorry lol

    • 2 years ago
  2. awesomeness123 Group Title
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    @Hero promise this is my last today

    • 2 years ago
  3. awesomeness123 Group Title
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    im still confused bout this

    • 2 years ago
  4. awesomeness123 Group Title
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    |dw:1351893998329:dw|

    • 2 years ago
  5. awesomeness123 Group Title
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    so first -5,0 and 0,3 i plug into the y2-y1 thing

    • 2 years ago
  6. awesomeness123 Group Title
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    then i got 3/5

    • 2 years ago
  7. awesomeness123 Group Title
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    since its perp i change it to -5/3

    • 2 years ago
  8. awesomeness123 Group Title
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    then i do the y-y1 formula with the point 2,-3

    • 2 years ago
  9. awesomeness123 Group Title
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    (btw I need u to check it

    • 2 years ago
  10. awesomeness123 Group Title
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    then im confused help!

    • 2 years ago
  11. JakeV8 Group Title
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    is (2,-3) the point that the perpendicular line is supposed to run through? I think you're almost there... you have the perp slope as -5/3, and you know the point, and it sounds like you know the formula... the point slope form of a line is y - y1 = m(x -x1) where (x1, y1) is your point, and m is your slope.

    • 2 years ago
  12. awesomeness123 Group Title
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    please hurry as i need to go soon

    • 2 years ago
  13. awesomeness123 Group Title
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    yes

    • 2 years ago
  14. awesomeness123 Group Title
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    see i did that but i didnt get any of the options

    • 2 years ago
  15. JakeV8 Group Title
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    so it's y - (-3) = (-5/3)(x-2) y + 3 = -5/3x -10/3 y = -5/3 x -19/3

    • 2 years ago
  16. awesomeness123 Group Title
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    but is that an option?

    • 2 years ago
  17. JakeV8 Group Title
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    oh... that's not up there. Hm. Is that the problem? The way you posted this, it didn't show the original line or the point. to run the perp line through.

    • 2 years ago
  18. awesomeness123 Group Title
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    hold on ill attach a file!

    • 2 years ago
  19. awesomeness123 Group Title
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    • 2 years ago
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  20. JakeV8 Group Title
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    The problem is your slope. The actual line looks like it goes through (-5,0), but it doesn't... it's just close. The actual real slope is 2/3. So your perp slope is -3/2 And your equation becomes: y - (-3) = -3/2 (x - 2) y + 3 = -3/2 x + 3 y = -3/2 x

    • 2 years ago
  21. awesomeness123 Group Title
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    thank you!!! SO MUCH!! muah thxx

    • 2 years ago
  22. JakeV8 Group Title
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    you would have gotten it correct if you had been able to read that graph better. Your approach seemed fine, but since you read the slope incorrectly, the answers weren't working out to match your choices.

    • 2 years ago
  23. awesomeness123 Group Title
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    got it!

    • 2 years ago
  24. JakeV8 Group Title
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    glad to help :)

    • 2 years ago
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