anonymous
  • anonymous
1 5 10 10 5 1
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
you need to know that when expanding there is a simple rule to follow instead of formulae: (first + second) ^ 5 = 1 * first ^ 5 * second ^ 0 + 5 * first ^ 4 * second ^ 1 + 10 * first ^ 3 * second ^ 2 + 10 * first ^ 2 * second ^ 3 + 5 * first ^ 1 * second ^ 4 + 1 * first ^ 0 * second ^ 5 You can see those exponents: for first, exponent starts from 5 and decreases, and for second, it starts from 0 and increases
anonymous
  • anonymous
well...(3v)^5 is 3^5 * v^5...it depends what do you actually need: just expand the binomial or solve some kind of equation...
anonymous
  • anonymous
second one definitely...reason is that 3 * v IS first item, so it gets expanded as a whole, and 1 5 10 10 5 1 are coefficients that get multiplied whatever gets out of first^xxx second^xxx

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anonymous
  • anonymous
oh, okay ..thank you very much :))

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