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pathosdebater
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Please help... A plane heads west (180.0 degrees) at a speed of 400.0 mph. The wind's velocity is southeast (315.0 degrees) at 30. mph.
What is Ax, the magnitude of the original vector of the plane?
 one year ago
 one year ago
pathosdebater Group Title
Please help... A plane heads west (180.0 degrees) at a speed of 400.0 mph. The wind's velocity is southeast (315.0 degrees) at 30. mph. What is Ax, the magnitude of the original vector of the plane?
 one year ago
 one year ago

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ivanmlerner Group TitleBest ResponseYou've already chosen the best response.0
What do you mean by Ax, I didn't get it
 one year ago

pathosdebater Group TitleBest ResponseYou've already chosen the best response.0
Ax is the magnitude of the original vector of the plane.
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.0
Yes, I read it, but what does this vector mean?
 one year ago

pathosdebater Group TitleBest ResponseYou've already chosen the best response.0
Well I'm guessing that the equation forms a triangle. One side is west (180.0 degrees) at a speed of 400.0 mph and another is southeast (315.0 degrees) at 30. mph. I think Ax is the final vector of the triangle.
 one year ago

pathosdebater Group TitleBest ResponseYou've already chosen the best response.0
It is asking for the length of the unknown side
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.0
dw:1351909145239:dwUsing vectors, we see that the velocity vector has value 400 in the direction of x, and the wind velocity vector has value cos(45°)*30 in the direction of x. The y component of the wind velocity vector is sin(45°)*30 Now, we have that the vector you want is: (400, 0)(cos(45°)*30, sin(45°)*30)=(400+sqrt(2)*15, sqrt(2)*15) and the magnitude of the vector is: sqrt((400+sqrt(2)*15)^2+2*15^2)
 one year ago

hubertH Group TitleBest ResponseYou've already chosen the best response.0
dw:1351980839247:dw use cosine rule to get the unknown side
 one year ago

hubertH Group TitleBest ResponseYou've already chosen the best response.0
the answer shoul be 379,38mph
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.0
Don't forget when using direction headings, North is 0 degrees amd South is 180 degrees, and west is 270 degrees (not 180 degrees)
 one year ago

radar Group TitleBest ResponseYou've already chosen the best response.0
Please help... A plane heads west (270.0 degrees) at a speed of 400.0 mph. The wind's velocity is southeast (135.0 degrees) at 30. mph. Would be describing the situation and the wind direction is in the direction that it is going. Not coming from as is the normal reporting of wind.
 one year ago
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