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anonymous
 4 years ago
Solve the initial value problem:
x(dy/dx)+y(x) = 9y(x)^(2), y(1) = 1
anonymous
 4 years ago
Solve the initial value problem: x(dy/dx)+y(x) = 9y(x)^(2), y(1) = 1

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x \frac{ dy }{dx } + y(x) = 9y(x)^2 , y(1) =1\] Just the equation a little neater

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would solve for dy/dx and intergrate.

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0the ex's int he brackets are just indicating the independent variable right?\[x \frac{ \text dy }{\text dx } + y = 9y^2 , \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and we know y(1) = 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I believe so, that's just how its been written. I'll try solving for dy/dx and integrating then,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So I would sub those in.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2u realize that you can separate the variables easily here ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx } = \frac{ 9y(x)^2y }{ x }\] Not too familiar with these problems, but basically i need to integrate that, no?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2u bring all terms of one variable on one side of = sign, like this : \(\large \frac{1}{9y^2y}dy=\frac{1}{x}dx\) then integrate

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2can u integrate both sides now ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0think i got it, left an x over the y side so i confused my self. \[1 = \ln(19y)\ln(y)\]

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2u integrated yvariable correctly , but what about \(\int (1/x)dx\) its not =1

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2i meant u should get something like this : \(\ln x=ln(19y)lny+c\) then use logarithmic properties to simplify

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, catching on think i figured out what i did wrong when i integrated last anyway.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Maybe y = \[\frac{ 1 }{ x+9 }\] May be a final solution, just simplifying the equation?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2ln cx= ln (19y)/y cxy= (19y) now use y(1) = 1 to find c.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2u got this simplification ? >ln cx= ln (19y)/y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup, \[C(1)(1)=19(1)\] \[C=10\] \[C=10\] \[10xy=(19y)\]

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.210xy =19y or 10xy9y+1=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahh, forgot the negative, think i have enough to try a few more of these questions any way. Thank you. :)
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